我很难理解 dateutil.relativedelta 的行为。 我知道如果我使用 relativedelta doc 中指定的否定参数,relativedelta 可能会返回过去的日期.
但是,当我提供正参数时,我希望它总是返回一个 future 的日期……这似乎是对的吧?
我的用例如下:我们是星期二,现在是 8:35。我想在 6:00 获取最近的星期一和星期二的日期。
这是我所做的。第一个结果对我来说似乎是正确的,而第二个结果是错误的。
>>> import datetime
>>> now = datetime.datetime.now()
>>> now
datetime.datetime(2016, 11, 29, 8, 35, 23, 786349)
>>> from dateutil import relativedelta
>>> now.weekday()
1
>>> now + relativedelta.relativedelta(weekday=0, hour=6, minute=0) # should give a time in the future
datetime.datetime(2016, 12, 5, 6, 0, 23, 786349) # here this is correct, in the future
>>> now + relativedelta.relativedelta(weekday=1, hour=6, minute=0) # should give a time in the future
datetime.datetime(2016, 11, 29, 6, 0, 23, 786349) # but this is in the past / I would expect result (2016, 12, 6, 6, 0, 23, 786349)
那么,我是不是做错了什么?
最佳答案
因此,根据您的初始日期,您实际上是早上 8 点,但您使用 hour
将目标定为早上 6 点。参数,如果你想增加一小时,你应该使用 hours
和 minutes
分别
>>> now
datetime.datetime(2016, 11, 29, 3, 5, 41, 763818)
>>> now.weekday()
1
>>> now + relativedelta.relativedelta(weekday=1, hour=1)
datetime.datetime(2016, 11, 29, 1, 5, 41, 763818) # Notice how it's in the past
>>> now + relativedelta.relativedelta(weekday=1, hours=1)
datetime.datetime(2016, 11, 29, 4, 5, 41, 763818) # Notice how it's one hour in the future
>>> n + relativedelta.relativedelta(weekday=1, hour=6, minute=0, weeks=1)
datetime.datetime(2016, 12, 6, 6, 0, 41, 763818)
关于python - 为什么带有正参数的 relativedelta 返回过去的日期?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40860505/