我有这样的代码
# -*- coding: utf-8 -*-
class OP(object):
def RECEIVE_MESSAGE(self):
print("done")
def NOTIFIED_INVITE_INTO_GROUP(self):
print("done")
但是当我运行它的时候出现了一些错误
Traceback (most recent call last):
File "run.py", line 2, in <module>
from van import ERVAN
File "/home/server/.pub/van.py", line 4, in <module>
from op import OP
File "/home/server/.pub/op.py", line 9
def NOTIFIED_INVITE_INTO_GROUP(self):
^
IndentationError: unindent does not match any outer indentation level
有什么解决办法吗？它只有 10 行，但让我大吃一惊
这是您的代码，其中空格被点替换:
#.-*-.coding:.utf-8.-*-
class.OP(object):
..def.RECEIVE_MESSAGE(self):
......print("done")
..def.NOTIFIED_INVITE_INTO_GROUP(self):
....print("done")
如您所见，第一个 print("done") 语句缩进了 6 个空格 - 将其更改为 4 以解决问题。
更好的是，按照 PEP 8 的建议，更改所有缩进，使它们成为 4 个空格的倍数(即 0、4、8、12 等)
#.-*-.coding:.utf-8.-*-
class.OP(object):
....def.RECEIVE_MESSAGE(self):
........print("done")
....def.NOTIFIED_INVITE_INTO_GROUP(self):
........print("done")
更多细节，来自Python: Myths about Indentation
How does the compiler parse the indentation? The parsing is
well-defined and quite simple. Basically, changes to the indentation
level are inserted as tokens into the token stream.
The lexical analyzer (tokenizer) uses a stack to store indentation
levels. At the beginning, the stack contains just the value 0, which
is the leftmost position. Whenever a nested block begins, the new
indentation level is pushed on the stack, and an "INDENT" token is
inserted into the token stream which is passed to the parser. There
can never be more than one "INDENT" token in a row.
When a line is encountered with a smaller indentation level, values
are popped from the stack until a value is on top which is equal to
the new indentation level (if none is found, a syntax error occurs).