python - 仅打印奇数字典键及其项

Question

我有以下字典，我只需要打印奇数(1、3 ...)的字典。我该怎么做呢？

zen = {
    1: 'Beautiful is better than ugly.',
    2: 'Explicit is better than implicit.',
    3: 'Simple is better than complex.',
    4: 'Complex is better than complicated.',
    5: 'Flat is better than nested.',
    6: 'Sparse is better than dense.',
    7: 'Readability counts.',
    8: 'Special cases aren't special enough to the rules.',
    9: 'Although practicality beats purity.',
   10: 'Errors should never pass silently.'
   }

到目前为止我有:

for c in zen:
print (c , zen[c][:])

Answer 1

如果你的键是数字:

for i in range(1,len(zen),2):
    print(zen[i])

它从 1 开始，步进为 2，所以我只会做赔率

正如评论中的用户指出的那样，有时并非所有键都存在:

for i in zen:
    if (i%2 == 0):
         print(zen[i])

另一种更短的方法是列表理解，但是它有点不寻常，因为您真的不需要列表。

[print(zen[i]) for i in zen if i%2==1]