python - 将值列表拆分为字典列表

Question

我有这样的键值字典:

[{"key1" : ['1', '2'], "key2" : ['john', 'marvel']}, {"key1" : ['150', '120'], "key2" : ['gandalf', 'sam']}]

我想得到这样的东西:

[ {key1 : '1', key2 : 'john'}, {key1 : '2', key2 : 'marvel'}, {key1 : '150', key2 : 'gandalf'}, {key1 : '120', key2 : 'sam'}]

我被卡住了，我想嵌入循环，但我不知道怎么做。

Answer 1

你可以使用 list comprehension :

data = [{"key1": ['1', '2'], "key2": ['john', 'marvel']}, {"key1": ['150', '120'], "key2": ['gandalf', 'sam']}]

keys = ['key1', 'key2']
result = [dict(zip(keys, items)) for d in data for items in zip(*(d[k] for k in keys))]

print(result)

输出

[{'key2': 'john', 'key1': '1'}, {'key2': 'marvel', 'key1': '2'}, {'key2': 'gandalf', 'key1': '150'}, {'key2': 'sam', 'key1': '120'}]

上面的列表理解等价于下面的for循环:

result = []
for d in data:
    for items in zip(*(d[k] for k in keys)):
        result.append(dict(zip(keys, items)))