python - 打开并读取以空格分隔的 txt 文件

Question

我有一个空格分隔的 txt 文件，如下所示:

2004          Temperature for KATHMANDU AIRPORT       
        Tmax  Tmin
     1  18.8   2.4 
     2  19.0   1.1 
     3  18.3   1.7 
     4  18.3   1.0 
     5  17.8   1.3 

我想分别计算 Tmax 和 Tmin 的平均值。但是，我很难阅读 txt 文件。我试过 this link like .

import re
list_b = []
list_d = []

with open('TA103019.95.txt', 'r') as f:
    for line in f:
        list_line = re.findall(r"[\d.\d+']+", line)
        list_b.append(float(list_line[1])) #appends second column
        list_d.append(float(list_line[3])) #appends fourth column

print list_b
print list_d

但是，它给我错误: IndexError:列表索引超出范围 这里有什么问题？

Answer 1

解决这个问题的一个简单方法是使用 split()功能。 当然，你需要去掉前两行:

with io.open("path/to/file.txt", mode="r", encoding="utf-8") as f:
    next(f)
    next(f)
    for line in f:
        print(line.split())

你得到:

['1', '18.8', '2.4']
['2', '19.0', '1.1']
['3', '18.3', '1.7']
['4', '18.3', '1.0']
['5', '17.8', '1.3']

引用文档:

If sep is not specified or is None, a different splitting algorithm is applied: runs of consecutive whitespace are regarded as a single separator, and the result will contain no empty strings at the start or end if the string has leading or trailing whitespace.