python - 如何转换每列的每一行中包含列表的数据框

Question

我有以下 dataframe，它是 for 循环的输出之一。

df = pd.DataFrame()

df['Score'] = [['0-0','1-1','2-2'],['0-0','1-1','2-2']]
df ['value'] =[[0.08,0.1,0.15],[0.07,0.12,0.06]]
df ['Team'] = ['A','B']

我想将每一行列表的每个元素转换为一列的每个元素。 以下是预期的输出。

谁能帮我改造一下？

谢谢，

齐普

Answer 1

使用np.concatenate :

import pandas as pd 
import numpy as np 

x = [['0-0','1-1','2-2'],['0-0','1-1','2-2']]
y = [[0.08,0.1,0.15],[0.07,0.12,0.06]]
z = ['A','B']
df = pd.DataFrame()

df['Score'] = np.concatenate(x)
df ['value'] = np.concatenate(y)
df['Team'] = np.repeat(z, len(df)/len(z))
print(df)

输出:

  Score  value Team                                                                                                                          
0   0-0   0.08    A                                                                                                                          
1   1-1   0.10    A                                                                                                                          
2   2-2   0.15    A                                                                                                                          
3   0-0   0.07    B                                                                                                                          
4   1-1   0.12    B                                                                                                                          
5   2-2   0.06    B