python - 为什么我的 python 代码不能正常运行？

Question

我的 python 代码如下，但它不起作用。

import random

secret = random.randint (1, 99)
guess = 0
tries = 0

print "AHOY! I'm the Dread Pirate Oliver and I have a secret!"
print "I will tell you where my treasure is buried if you can guess the number that I'm thinking of."
print "It is a number from 1 to 99. I'll give you 6 tries."

while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "THE FIRST WORD IS: Awesome"
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()

import random

secret = random.randint (1, 99)
guess = 0
tries = 0

print "AHOY THERE!"
print "ME AGAIN"
print "I will tell you the second word if you can guess the number that I'm thinking of."
print "It is a number from 1 to 99. I'll give you 6 tries."

while guess != secret and tries < 6:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "THE SECOND WORD IS: Land"
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()    

import random

secret = random.randint (1, 3)
guess = 0
tries = 0

print "AHOY! One more thing"
print "It is a number from 1 to 3. I'll give you 1 try."

while guess != secret and tries < 1:
    guess = input ("What's yer guess? ")
    if guess < secret:
        print "Too low ye scurvy dog!"
    elif guess > secret:
        print "Too high, landlubber!"
    tries = tries + 1

if guess == secret:
    print "Avast! Ye got it! Found ma secret number, ye did!"
    print "It's buried in the sand at 36 degrees North, 48 degrees east."
else:
    print "No more guesses! Better luck next time, Matey!"
    print "Ma secret number wuz", secret
raise SystemExit()
import random

secret = random.randint (1, 99)
guess = 0
tries = 0
print "Congratz. You won!"

在 raise SystemExit() 部分，我希望这个人如果没有猜到最后一点就无法继续。它甚至没有启动，但是当我取出 raise SystemExit() 时，它会工作但会继续运行，即使他们没有猜对。我应该放什么来做我想做的事？

Answer 1

这一行应该缩进，以便它是 else block 的一部分，否则即使猜测正确，它也会一直执行:

raise SystemExit()

调用 sys.exit() 可能会更好。

此外，如果你想做某事两次，而不是复制和粘贴你的代码，你应该创建一个函数并调用它两次:

def play():
    # ...

number_of_games = 2
for i in range(number_of_games):
    play()