我正在研究 Orange ,我在 OSX (10.6.5) 中遇到了这个问题,菜单栏名称是“Python”而不是橙色。这是一个 python/qt 应用程序。我需要改变什么?
澄清一下:
- qt 应用程序,不是 cli,不在终端中运行。
我的信息.plist:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple Computer//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
<key>CFBundleDisplayName</key>
<string>YOORANGE</string>
<key>CFBundleExecutable</key>
<string>Orange</string>
<key>CFBundleIconFile</key>
<string>orange.icns</string>
<key>CFBundleIdentifier</key>
<string>si.ailab.Orange</string>
<key>CFBundleInfoDictionaryVersion</key>
<string>6.0</string>
<key>CFBundleName</key>
<string>Orange</string>
<key>CFBundleGetInfoString</key>
<string>Orange, component-based data mining software</string>
<key>CFBundlePackageType</key>
<string>APPL</string>
<key>CFBundleSignature</key>
<string>Orng</string>
<key>CFBundleShortVersionString</key>
<string>1.0.0</string>
<key>CFBundleVersion</key>
<string>1.0.0</string>
<key>CFBundleDocumentTypes</key>
<array>
<dict>
<key>CFBundleTypeExtensions</key>
<array>
<string>ows</string>
</array>
<key>CFBundleTypeName</key>
<string>Orange Canvas Schema</string>
<key>CFBundleTypeOSTypes</key>
<array>
<string>OWSf</string>
</array>
<key>CFBundleTypeIconFile</key>
<string>schema.icns</string>
<key>CFBundleTypeRole</key>
<string>Viewer</string>
<key>LSIsAppleDefaultForType</key>
<true/>
</dict>
</array>
</dict>
</plist>
这里是 Orange 启动脚本,经过修改以尝试使用符号链接(symbolic link)。显然有些工作有效:)
#!/bin/bash
BUNDLE_DIR=`dirname $0`/../
BUNDLE_DIR=`perl -MCwd=realpath -e 'print realpath($ARGV[0])' $BUNDLE_DIR`/
FRAMEWORKS_DIR="$BUNDLE_DIR"Frameworks/
CANVAS_FILE="$FRAMEWORKS_DIR"Python.framework/Versions/2.6/lib/python2.6/site-packages/orange/OrangeCanvas/orngCanvas. pyw
cp "$FRAMEWORKS_DIR"Python.framework/Resources/Python.app/Contents/MacOS/{Python-32,AWESOME}
PYTHONEXECUTABLE="$FRAMEWORKS_DIR"Python.framework/Resources/Python.app/Contents/MacOS/AWESOME
PYTHONHOME="$FRAMEWORKS_DIR"Python.framework/Versions/2.6/
#DYLD_FRAMEWORK_PATH="$FRAMEWORKS_DIR"${DYLD_FRAMEWORK_PATH:+:$DYLD_FRAMEWORK_PATH}
DYLD_FRAMEWORK_PATH="$FRAMEWORKS_DIR":"$BUNDLE_DIR"Resources/Qt4/lib${DYLD_FRAMEWORK_PATH:+:$DYLD_FRAMEWORK_PATH}
export PYTHONEXECUTABLE
export PYTHONHOME
export DYLD_FRAMEWORK_PATH
export DYLD_LIBRARY_PATH="$BUNDLE_DIR"Resources/openbabel/lib/:"$BUNDLE_DIR"Resources/openbabel/lib/openbabel/2.2.3/:$ DYLD_LIBRARY_PATH
# LaunchServices passes the Carbon process identifier to the application with -psn paramter - we do not want it
if [[ "$1" == -psn* ]] ; then
shift
fi
echo "$0"
echo "$PYTHONEXECUTABLE"
echo "$@"
exec -a "$0" "$PYTHONEXECUTABLE" "$CANVAS_FILE" "$@"
最佳答案
我想提出另一种解决方案。 它使用 Cocoa 来设置应用程序名称, 无需摆弄符号链接(symbolic link)。 在使用 PyQt 之前,在您的主模块中尽早运行它。
if sys.platform.startswith('darwin'):
# Set app name, if PyObjC is installed
# Python 2 has PyObjC preinstalled
# Python 3: pip3 install pyobjc-framework-Cocoa
try:
from Foundation import NSBundle
bundle = NSBundle.mainBundle()
if bundle:
app_name = os.path.splitext(os.path.basename(sys.argv[0]))[0]
app_info = bundle.localizedInfoDictionary() or bundle.infoDictionary()
if app_info:
app_info['CFBundleName'] = app_name
except ImportError:
pass
关于python - 在 OSX 中,将应用程序名称从 "python"更改为,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5047734/