我有一本看起来像这样的字典:
myDict = {
'SER12346': {'serial_num': 'SER12346', 'site_location': 'North America'},
'ABC12345': {'serial_num': 'ABC12345', 'site_location': 'South America'},
'SER12345': {'serial_num': 'SER12345', 'site_location': 'North America'},
'SER12347': {'serial_num': 'SER12347', 'site_location': 'South America'},
'ABC12346': {'serial_num': 'ABC12346', 'site_location': 'Europe'}
}
我的目标是根据每个子词典的 site_location
和 serial_num
对这本词典进行排序。
使用我在这个问题中找到的代码 - Sort a dictionary of dictionaries python - 我能够对其进行排序,但这并不完全是我所期望的。
这是我的代码:
import pprint
items = ((k, k2, v) for k in myDict for k2, v in myDict[k].items())
ordered = sorted(items, key=lambda x:x[-1], reverse=False)
pprint.pprint(ordered)
这是我得到的结果:
[('ABC12346', 'site_location', 'Europe'),
('SER12345', 'site_location', 'North America'),
('SER12346', 'site_location', 'North America'),
('SER12347', 'site_location', 'South America'),
('ABC12345', 'site_location', 'South America'),
('ABC12346', 'serial_num': 'ABC12346'),
('SER12345', 'serial_num': 'SER12345'),
('SER12346', 'serial_num': 'SER12346'),
('SER12347', 'serial_num': 'SER12347'),
('ABC12345', 'serial_num': 'ABC12345')]
虽然我期待更像这样的东西:
{
'ABC12346': {'serial_num': 'ABC12346', 'site_location': 'Europe'}
'SER12345': {'serial_num': 'SER12345', 'site_location': 'North America'},
'SER12346': {'serial_num': 'SER12346', 'site_location': 'North America'},
'SER12347': {'serial_num': 'SER12347', 'site_location': 'South America'},
'ABC12345': {'serial_num': 'ABC12345', 'site_location': 'South America'},
}
实际结果是将序列号和站点位置分开。我想将它们放在排序的对象中。我该怎么做?
最佳答案
这是你想要的吗?
dicts = [{k: v} for (k,v) in myDict.items()]
dicts.sort(key=lambda d: (d.values()[0]['site_location'], d.values()[0]['serial_num'],))
执行的输出:
import pprint
pprint.pprint(dicts)
是:
[{'ABC12346': {'serial_num': 'ABC12346', 'site_location': 'Europe'}},
{'SER12345': {'serial_num': 'SER12345', 'site_location': 'North America'}},
{'SER12346': {'serial_num': 'SER12346', 'site_location': 'North America'}},
{'ABC12345': {'serial_num': 'ABC12345', 'site_location': 'South America'}},
{'SER12347': {'serial_num': 'SER12347', 'site_location': 'South America'}}]
编辑:我正在回答您对输出格式的回答,但这可能更有意义:
dicts = myDict.items()
dicts.sort(key=lambda (k,d): (d['site_location'], d['serial_num'],))
输出:
[('ABC12346', {'serial_num': 'ABC12346', 'site_location': 'Europe'}),
('SER12345', {'serial_num': 'SER12345', 'site_location': 'North America'}),
('SER12346', {'serial_num': 'SER12346', 'site_location': 'North America'}),
('ABC12345', {'serial_num': 'ABC12345', 'site_location': 'South America'}),
('SER12347', {'serial_num': 'SER12347', 'site_location': 'South America'})]
关于python - 根据多个子字典值对字典字典进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11346111/