假设我有一个名字列表。我希望能够将这些作为实例函数动态地添加到类实例中。我知道 types.MethodType 但我是从那里到这里的新手。基本上我想做的是:
class foo( object ):
def __init__(self):
pass
f = foo()
names = ["a","b","c"]
for name in names:
add name() to f # not sure what to do here
# what I wanted added to instance "f" is this for each name:
def name(self, *args, **kwargs):
print( "My name is %s" % inspect.stack()[0][3] )
print( "__called, args=%r, **kwargs=%r" % (args, kwargs) )
f.a() # ==> calls f.a()
f.b(1,2,3) # calls f.b(1,2,3 )and so on
最佳答案
如果将函数创建为嵌套函数会更容易; name
是从嵌套范围中获取的变量:
import types
def buildMethod(name, instance):
def namefunc(self, *args, **kwargs):
print "My name is %s" % name
print "__called, args=%r, **kwargs=%r" % (args, kwargs)
namefunc.__name__ = name
setattr(instance, name, types.MethodType(namefunc, instance, type(instance)))
f = foo()
names = ["a","b","c"]
for name in names:
buildMethod(name, f)
这导致:
>>> f.a
<bound method instance.a of <__main__.foo instance at 0x100d8e560>>
>>> f.a.__name__
'a'
>>> f.a()
My name is a
__called, args=(), **kwargs={}
>>> f.b()
My name is b
__called, args=(), **kwargs={}
>>> f.c()
My name is c
__called, args=(), **kwargs={}
关于python - 我希望能够动态地向 python 类添加函数,而事先不知道它们的名称,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13650784/