有什么方法可以将变量传递给所有模板吗?例如我有一个 View 包含
render_to_response('page.html', dictionary, \
context_instance = RequestContext(request))
我想将另一个不在字典中的变量传递给模板文件。
目的是什么?假设我在所有 View (几百个)中都需要这个变量,而且我很想在不触及字典的情况下将这个变量传递给模板文件。顺便说一句,这个变量是一个函数的结果,它有一个参数(请求)。
可行吗?
最佳答案
您需要编写自定义 context processor .
A context processor has a very simple interface: It’s just a Python function that takes one argument, an
HttpRequest
object, and returns a dictionary that gets added to the template context. Each context processor must return a dictionary.Custom context processors can live anywhere in your code base. All Django cares about is that your custom context processors are pointed-to by your
TEMPLATE_CONTEXT_PROCESSORS
setting.
例如:
# in project/context_processors.py
def add_extra_variable(request):
return {'extra': myfunction(request)}
# in settings.py:
TEMPLATE_CONTEXT_PROCESSORS = (
"django.contrib.auth.context_processors.auth",
"django.core.context_processors.debug",
"django.core.context_processors.i18n",
"django.core.context_processors.media",
"django.core.context_processors.static",
"django.core.context_processors.tz",
"django.contrib.messages.context_processors.messages",
"project.context_processors.add_extra_variable"
)
P.S.:如果您使用 render
而不是 render_to_response
,则不需要传递 RequestContext
。
render('page.html', dictionary)
关于python - Django 查看模板的默认值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15545952/