python - 为什么在这种特殊情况下没有定义 y ？

Question

我是 Python 2.7 的新手，我尝试创建一个简单的骰子游戏，但是我在让计算机识别 y 时遇到了一些困难，因为无论我做什么，它都不会将答案识别为 y 或 n。这是下面的代码。

import random
a = random.randint(1, 6)
b = random.randint(1, 6)
points = 0
strikes = 0

def main():
    print """Welcome to the two dice game. Depending on the result, you will earn a point or a strike. Three strikes end the game. Good luck!"""
    anwser = input('Play? y for yes, n for no')
    if anwser == "y":
       print a
       print b
       if a == b:
          print ("Congrats! You earned a point!")
          points = points + 1
          main()
    else:
        print("That's a strike...")
        strikes = strikes + 1
        if strikes == 3:
            print("That's three strikes, game over.")
            break
        else:
            main()
    if anwser == n:
       print ("Game over. You earned this many points.")
       print points

main()

Answer 1

input() 实际上会尝试评估您传递给它的任何内容。您需要 raw_input()。

参见 this question有关 input() 与 raw_input() 的更多信息。