我有一个 list
bulk_order
Out[230]:
[3 523
Name: order_id, dtype: object]
我有一个数组。它是一个系列，但我正在使用 values
clusters_order_ids.values
Out[231]:
array([['520', '521', '524', '527', '532'], ['528'], ['531'],
['525', '526', '533'], ['519', '523', '529', '534', '535'], ['530']],
dtype=object)
现在我想检查 list element 523 是否存在于上面的数组中，如果存在我想删除它。
我正在用 python 进行跟踪
bulk_order in clusters_order_ids.values
但它给了我 False 输出
最佳答案
您的列表不是列表，而是列表的列表。
如果你想删除包含列表 ['523'] 中的内容的整个列表:
orders = [['520', '521', '524', '527', '532'], ['528'], ['531'], ['525', '526', '533'], ['519', '523', '529', '534', '535'], ['530']]
remove_order_with_ids = ['523'] # or bulk_order
orders = [order for order in orders if not set(remove_order_with_ids).intersection(set(order))]
print orders
# [['520', '521', '524', '527', '532'], ['528'], ['531'], ['525', '526', '533'], ['530']]
如果您只想从内部列表中删除 ['523'] 中的项目:
orders = [['520', '521', '524', '527', '532'], ['528'], ['531'], ['525', '526', '533'], ['519', '523', '529', '534', '535'], ['530']]
remove_order_with_id = ['523'] # or bulk_order
new_orders = []
for order in orders:
new_orders.append([item for item in order if item not in remove_order_with_id])
print new_orders
# [['520', '521', '524', '527', '532'], ['528'], ['531'], ['525', '526', '533'], ['519', '529', '534', '535'], ['530']]
关于python - 如何检查列表元素是否存在于python中的数组中，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/34794037/