python - 如何在预期中看到输出？

Question

我写了这个程序:

[mik@mikypc ~]$ cat ftp.py 
 #!/usr/bin/env python

 # This connects to the rediris ftp site
 # 
 import pexpect
 child = pexpect.spawn('ftp ftp.rediris.es')

 child.expect('Name .*: ')
 child.sendline('anonymous')
 child.expect('ftp> ')
 child.sendline('noah@example.com')
 child.expect('ftp> ')
 child.sendline('lcd /tmp')
 child.expect('ftp> ')
 child.sendline('pwd')
 child.expect('ftp> ')
 child.sendline('bye')

[mik@mikypc ~]$ ./ftp.py 
[mik@mikypc ~]$ 
[mik@mikypc ~]$ 
[mik@mikypc ~]$ 

但是我看不到输出。我怎么会看到它？我执行它时什么也看不到。我怎样才能看到输出？

Answer 1

根据pexpect doc :

The logfile_read and logfile_send members can be used to separately log the input from the child and output sent to the child. Sometimes you don’t want to see everything you write to the child. You only want to log what the child sends back. For example:

child = pexpect.spawn('some_command')
child.logfile_read = sys.stdout

You will need to pass an encoding to spawn in the above code if you are using Python 3.
To separately log output sent to the child use logfile_send:

child.logfile_send = fout 

请看下面的例子:

[STEP 105] # cat foo.py
import pexpect, sys

re_PS1 = 'bash-[.0-9]+[$#] $'

proc = pexpect.spawn('bash --norc')
if len(sys.argv) != 1:
    if sys.version_info[0] < 3:
        proc.logfile_read = sys.stdout
    else:
        proc.logfile_read = sys.stdout.buffer

proc.expect(re_PS1)

proc.sendline("echo hello world")
proc.expect(re_PS1)

proc.sendline('exit')
proc.expect(pexpect.EOF)
proc.close()

[STEP 106] # python foo.py
[STEP 107] # python foo.py foo
bash-4.4# echo hello world
hello world
bash-4.4# exit
exit
[STEP 108] #