python - 在函数本身中打印函数名称

Question

我有很多功能，例如:

def DBworker_thatdoes_job7():
    print "DBworker_thatdoes_job7 starting..."

    ... the actual code here ...

    print "DBworker_thatdoes_job7 finished."

如何在不对函数名称进行硬编码的情况下做到这一点？这是我想要实现的目标:

def DBworker_thatdoes_job7():
    print thisfunction.name + " starting..."
    ...

def DBworker_thatdoes_cleaning18():
    print thisfunction.name + " starting..."
    ...

注意:我已经看过 How to get a function name as a string in Python?但我真的没有看到在这里做这件事的好方法。另外，这个问题接近Determine function name from within that function (without using traceback)但这里适用于在启动和结束时记录函数名称的特定用例，因此不完全重复。

Answer 1

你可以使用装饰器:

def start_finish(f):
    def new_f(*args, **kwargs):
        print("starting", f.__name__)
        f(*args, **kwargs)
        print("finished", f.__name__)
    return new_f

@start_finish
def function():
    print('function body')

function()

这打印:

starting function
function body
finished function