python - 如何从 python 列表中任何特定索引处的句子中提取特定字符串？

Question

names=['alex','peter','sana','alice']

info=['alex is working on os_10 coolest one',
'peter is working on OS_9 which is not that cool', 
'sana is working on OS_7 which is quite old', 
'Thanos is also using os_10', 
'alice is fan of thanos so she also uses os_10']

#我试过了

 v=[]

    for name in names:
        a= [x for x in info if name in x]
        #print(a)
        v.append(a)

    print(v)

首先，我制作了一个列表，其中仅包含名字在列表中的那个人的信息 现在我想要像 alex: os_10, peter: OS_9 等这样的 o/p

Answer 1

您可以拆分 文本并获取项目First 和Last 索引。

代码:

a = ['Alex is working on OS_10', 'Peter is working on OS_8', 'Sana is working on OS_7']
print(*[f"{t.split()[0]} {t.split()[-1]}" for t in a], sep=',\n')

输出:

Alex OS_10,
Peter OS_8,
Sana OS_7