python - 如果无法定位元素，Selenium 继续执行脚本

Question

我有一个问题，当我访问一个网站时，如果想检查元素是否显示和启用。如果是这样的话，我想打印一些东西。如果该元素未显示和启用，我想检查一个新元素，如果要打印某些内容，是否显示该元素。我希望你明白这一点。

当访问网站并且未检测到/显示第一个 IF 语句时，它给出错误而不是转到下一个 If 语句。

错误:

selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: //*[@id="errorLongContent"]

我已经尝试使用 try、expect 并将 if 语句更改为 elif。

我希望有人能帮助我。

from selenium import webdriver
from selenium.webdriver import Firefox
from selenium.webdriver.firefox.options import Options

# Setup browser for
options = Options()
profile = webdriver.FirefoxProfile()
driver = Firefox(executable_path='geckodriver', options=options, firefox_profile=profile)
driver.get("https://agar.io")

#Xpaths
PLAY_BUTTON_XPATH = '//*[@id="play"]'
PROXY_DENIES_CONNECTION = '//*[@id="errorLongContent"]'
TIMEOUT_XPATH1 = '//*[@id="errorTryAgain"]'


#checking for error
def mainfunction():
    while True:
        print("Starting")
        if driver.find_element_by_xpath(PROXY_DENIES_CONNECTION).is_enabled() and driver.find_element_by_xpath(
                PROXY_DENIES_CONNECTION).is_displayed():
            print("Proxy denies connection")
            driver.quit()

        if driver.find_element_by_xpath(TIMEOUT_XPATH1).is_enabled() and driver.find_element_by_xpath(
                TIMEOUT_XPATH1).is_displayed():
            print("Time out detected")
            driver.quit()

        if driver.find_element_by_xpath(PLAY_BUTTON_XPATH).is_enabled() and driver.find_element_by_xpath(
                PLAY_BUTTON_XPATH).is_displayed():
            print("Agar.io server is loaded")
            break

        else:
            continue

mainfunction()

编辑:尝试并排除

def mainfunction():
    while True:
        print("Starting")
        try:
            if driver.find_element_by_xpath(PROXY_DENIES_CONNECTION).is_enabled() and driver.find_element_by_xpath(
                    PROXY_DENIES_CONNECTION).is_displayed():
                print("Proxy denies connection")
                driver.quit()
        except:
            continue
        try:
            if driver.find_element_by_xpath(TIMEOUT_XPATH1).is_enabled() and driver.find_element_by_xpath(
                    TIMEOUT_XPATH1).is_displayed():
                print("Time out detected")
                driver.quit()
        except:
            continue

        try:
            if driver.find_element_by_xpath(PLAY_BUTTON_XPATH).is_enabled() and driver.find_element_by_xpath(
                    PLAY_BUTTON_XPATH).is_displayed():
                print("Agar.io server is loaded")
                break
        except:
            continue

当我运行它时，它会在无限循环中运行，只打印开始...

Answer 1

我将您的 if 语句放在“try/except”语句中，它运行时没有出现上述错误。

from selenium import webdriver
from selenium.webdriver import Firefox
from selenium.webdriver.firefox.options import Options

# Setup browser for
options = Options()
profile = webdriver.FirefoxProfile()
driver = Firefox(executable_path='geckodriver', options=options, firefox_profile=profile)
driver.get("https://agar.io")

#Xpaths
PLAY_BUTTON_XPATH = '//*[@id="play"]'
PROXY_DENIES_CONNECTION = '//*[@id="errorLongContent"]'
TIMEOUT_XPATH1 = '//*[@id="errorTryAgain"]'


#checking for error
def mainfunction():
    while True:
        print("Starting")
        try:
            if driver.find_element_by_xpath(PROXY_DENIES_CONNECTION).is_enabled() and driver.find_element_by_xpath(
                    PROXY_DENIES_CONNECTION).is_displayed():
                print("Proxy denies connection")
                driver.quit()
        except:
            pass
        try:
            if driver.find_element_by_xpath(TIMEOUT_XPATH1).is_enabled() and driver.find_element_by_xpath(
                    TIMEOUT_XPATH1).is_displayed():
                print("Time out detected")
                driver.quit()
        except:
            pass
        try:
            if driver.find_element_by_xpath(PLAY_BUTTON_XPATH).is_enabled() and driver.find_element_by_xpath(
                    PLAY_BUTTON_XPATH).is_displayed():
                print("Agar.io server is loaded")
                break
        except:
            pass

        else:
            continue

mainfunction()