Python 的装饰器函数有这个简单的模板
@A
@B
def C():
修改C函数为C=A(B(C));
举个更具体的例子
@request("POST", "%(channel)d/sequence/%(args)s")
@response("%d")
def outputSequence(self, channel, args):
self.checkDigitalChannelExported(channel)
self.checkPostingValueAllowed()
self.checkDigitalChannel(channel)
(period, sequence) = args.split(",")
period = int(period)
GPIO.outputSequence(channel, period, sequence)
return int(sequence[-1])
那么从上面,转换后的函数是
像请求(响应(outSequence(self,channel,args)))?
最佳答案
参数化装饰器的行为有点不同。 request
函数只接受参数,它是一个装饰器:
def request(arg1, arg2):
def my_decorator(func):
def wrapper():
#do something
return wrapper
return my_decorator
所以函数调用是这样的:
decorator = request(arg1, arg2)
response_decorator = decorator(response(arg1, arg2))
outputSequence = response_decorator(outputSequence(self, arg1, arg2))
这是一个小例子:
>>> def make_decorators(arg1, arg2):
def decorator(func):
def wrapper():
print("We got here!")
return wrapper
return decorator
>>> @make_decorators(1, 2)
def my_func():
pass
>>> my_func()
We got here!
关于python - Python 中的装饰器函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22213500/