python - 在 python 中格式化文本文件

Question

示例文本文件:

["abc","123","apple","red","<a href='link1'>zzz</a>"],

["abc","124","orange","blue","<a href='link1'>zzz</a>"],

["abc","125","almond","black","<a href='link1'>zzz</a>"],

["abc","126","mango","pink","<a href='link1'>zzz</a>"]

预期输出:

abc 123 apple red 'link1'>zzz

abc 124 orange blue 'link1'>zzz

abc 125 almond black 'link1'>zzz

abc 126 mango pink 'link1'>zzz

我只希望文件中没有大括号、由空格分隔的逗号，并且只获取行中最后一个元素的链接。

我尝试在 Python 中使用列表。

我不知道如何进行。猜猜，我在某处出错了。帮助将不胜感激。提前致谢:)

import sys
import re

Lines = [Line.strip() for Line in open (sys.argv[1],'r').readlines()]



for EachLine in Lines:
    Parts = EachLine.split(",")
    for EachPart in Parts:

        EachPart = re.sub(r'[', '', EachPart)
        EachPart = re.sub(r']', '', EachPart)

Answer 1

这可以使用以下脚本完成:

import csv
import re

with open('input.txt', 'r') as f_input, open('output.txt', 'w') as f_output:
    csv_input = csv.reader(f_input, delimiter='"')
    for cols in csv_input:
        if cols:
            cols = [x for x in cols[1:-1:2]]
            link = re.search(r"('.*?)<", cols[-1])
            if link:
                cols[-1] = link.group(1)

            f_output.write('{}\n'.format(' '.join(cols)))

这将为您提供 output.txt 包含:

abc 123 apple red 'link1'>zzz
abc 124 orange blue 'link1'>zzz
abc 125 almond black 'link1'>zzz
abc 126 mango pink 'link1'>zzz

更新 - 此代码的简化版本在 repl.it 上运行显示正确的输出。输入来自字符串，并显示输出。只需单击 Run 按钮即可。

更新 - 更新为跳过空行