python - Python 3 中的用户输入和排序列表

Question

我需要帮助来生成这样的输出:

1. Enter a member: samantha 
Names: ['Samantha']
2. Enter a member: susan 
Names: ['Samantha', 'Susan']
3. Enter a member: billy 
Names: ['Billy', 'Samantha', 'Susan']
4. Enter a member: billy
4. Enter a member: samantha
4. Enter a member: Jason 
Names: ['Billy', 'Jason', 'Samantha', 'Susan']
5. Enter a member: 

Members:
1. Billy
2. Jason
3. Samantha
4. Susan

我已经努力创建一个程序来执行此操作，但无济于事。我将在代码本身的问题中发表评论。预先感谢您的帮助。

def function():

    x = []
    #a = "1." # I tried to number the questions by adding these but it doesnt work
    while True:
        #a += 1
        name = input("Enter name: ").title()
        x.append(name)

        print("Names:", x)
        #if name == name: # this condition is made so that an input that is typed in again doesn't get included in the list
            #name = input("Enter name: ").title()

            # where should I add an insert() here to have the list alphabetically ordered?

        if not name: # pressing enter prints out the second half of the output, listing the members
            #print("\nMembers:", x).sort()
            break

function()

Answer 1

你做的几乎所有事情都是正确的，但问题是你在哪里打破了循环。您首先要附加名称，然后检查输入是否只是一个回车。因此，首先检查输入，然后将其附加到列表中。 这是我的代码:

def fun1():
    l = []
    while True:
        s = input("Enter a member: ")
        if not s:
            break
        l.append(s.title())
        print("Names:", l)
    l.sort()
    print("Members:")
    for i in range(0, len(l)):
        print(i+1,end = '')
        print(".", l[i])
fun1()

希望对您有所帮助。