sentence = “This makes array operations faster but less safe”
letter = ‘a’
函数必须打印
******a****a**a******a*******a***************a**
我尝试过使用替换和其他方法，但我仍然没有找到使它工作的方法
spam="This makes array operations faster but less safe"
print(spam.replace("b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z", "*"))
我很期待
******a****a**a******a*******a***************a**
最佳答案
使用正则表达式。
例如:
import re
sentence = 'This makes array operations faster but less safe'
print(re.sub(r"[^a]", r"*", sentence))
输出:
******a****a**a******a*******a***************a**
关于python - 如何替换句子中除一个字符外的所有字符，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/58168796/