python - If 语句 - 这是一个字符串吗？

Question

我有几本字典，每本都有相同的键和不同的定义。

尝试编写一个函数来确定键的定义是字符串还是列表。

什么都不打印...

lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

students = [lloyd,alice,tyler]

def compute_grades(ourstudents):
    for item in ourstudents:
        if item["name"] == type(str):
            print "YES"

compute_grades(students)

在这种情况下如何使用 if 语句来确定它是字符串还是列表？

Answer 1

使用isinstance:

>>> isinstance("foo", str) #Use basestring in py2.x
True
>>> isinstance([1, 2, 3], list)
True