我正在尝试编写一个程序，提示用户以字符串形式输入电话号码。输入可以包含字母，程序将字母(无论是大写还是小写)转换为数字，并保持所有其他字符不变。这是我到目前为止所拥有的:
def getNumber(uppercaseLetter):
if uppercaseLetter == 'A':
number = 2
elif uppercaseLetter == 'B':
number = 2
elif uppercaseLetter == 'C':
number = 2
elif uppercaseLetter == 'D':
number = 3
elif uppercaseLetter == 'E':
number = 3
elif uppercaseLetter == 'F':
number = 3
elif uppercaseLetter == 'G':
number = 4
elif uppercaseLetter == 'H':
number = 4
elif uppercaseLetter == 'I':
number = 4
elif uppercaseLetter == 'J':
number = 5
elif uppercaseLetter == 'K':
number = 5
elif uppercaseLetter == 'L':
number = 5
elif uppercaseLetter == 'M':
number = 6
elif uppercaseLetter == 'N':
number = 6
elif uppercaseLetter == 'O':
number = 6
elif uppercaseLetter == 'P':
number = 7
elif uppercaseLetter == 'Q':
number = 7
elif uppercaseLetter == 'R':
number = 7
elif uppercaseLetter == 'S':
number = 7
elif uppercaseLetter == 'T':
number = 8
elif uppercaseLetter == 'U':
number = 8
elif uppercaseLetter == 'V':
number = 8
elif uppercaseLetter == 'W':
number = 9
elif uppercaseLetter == 'X':
number = 9
elif uppercaseLetter == 'Y':
number = 9
elif uppercaseLetter == 'Z':
number = 9
return number
def translateNumber():
phoneNumber = str(input("Enter a string: "))
for char in phoneNumber:
if char in ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']:
getNumber(char)
return char
else:
return char
print(phoneNumber)
出于某种原因，我无法让它工作，而且我不确定问题出在哪里。有人可以帮我解决这个问题吗？谢谢!
最佳答案
不解释您的代码(已由 Chrisitan 完成)。这里只是一个方法:
>>> char_numbers = [('abc',2), ('def',3), ('ghi',4), ('jkl',5), ('mno',6), ('pqrs',7), ('tuv',8), ('wxyz',9)]
>>> char_num_map = {c:v for k,v in char_numbers for c in k}
>>> phone = "JUST 1 NUMBER"
>>> result = "".join(str(char_num_map.get(v,v)) for v in phone.lower())
>>> result
'5878 1 686237'
关于python - 在 Python 中将字母转换为电话号码的数字，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/22214652/