python - 文本冒险中匹配用户选择的问题。

Question

我目前正在使用 python 进行简单的文本冒险。基本上我希望 randint 选择 1 或 2，然后分配给 right_wire，然后 raw_input 为 wire_choice，然后匹配 2 以提供所需的结果。我相信你们无论如何都能弄清楚我在这里想做什么。我离这里很近还是真的很远？谢谢!

    right_wire = randint(1, 2)

    wrong_wire = 0

    if right_wire == 1:
        wrong_wire = 2
    elif right_wire == 2:
        wrong_wire = 1
    else:
        print "ERROR"

    while True:
        print "Which wire do you pull?"
        print
        print "1. The red one."
        print "2. The blue one."
        print
        wire_choice = raw_input('*>>*')

        if wire_choice == 1 and right_wire == 1:
            print "**BOMB DEFUSED**"
            return 'engineering2'
        elif wire_choice == 2 and right_wire == 2:
            print "**BOMB DEFUSED**"
            return 'engineering2'
        elif wire_choice == 1 and right_wire == 2:
            print "**FAILED**"
            return 'death'
        elif wire_choice == 2 and right_wire ==1:
            print "**FAILED**"
            return 'death'
        else:
            print no_understand

Answer 1

为什么不只是:

while True:
    print "Which wire do you pull?"
    print
    print "1. The red one."
    print "2. The blue one."
    print
    raw_input('*>>*')
    if randint(0, 1):
        print "**BOMB DEFUSED**"
        return 'engineering2'
    else:
        print "**FAILED**"
        return 'death'

/!\raw_input 返回一个字符串，你将返回值与一个整数进行比较，它永远不会匹配:

$ python
Python 2.6.6 (r266:84292, Dec 26 2010, 22:31:48) 
[GCC 4.4.5] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> 1 == "1"
False