我需要解析日期和时间。这是我得到的:
import time
a = time.strptime('Apr 28 2013 23:01', "%b %d %y %H:%M")
print a
但它给了我
Traceback (most recent call last):
File "/home/aaa/Documents/python_test.py", line 17, in <module>
a = time.strptime('Apr 28 2013 23:01', "%b %d %y %H:%M")
File "/usr/lib/python2.7/_strptime.py", line 467, in _strptime_time
return _strptime(data_string, format)[0]
File "/usr/lib/python2.7/_strptime.py", line 325, in _strptime
(data_string, format))
ValueError: time data 'Apr 28 2013 23:01' does not match format '%b %d %y %H:%M'
我做错了什么？
最佳答案
%y 对于 4 位数年份应该是 %Y...
来自docs :
%y Year without century as a decimal number [00,99].
%Y Year with century as a decimal number.
关于python - 无法在 Python 中解析日期，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16355437/