Python - 新手 : Why this simple if-elif (replication of the C case block) always produces the same result?

Question

这里是初学者。每当我输入指定的字符串时，任何人都可以解释和/或帮助我修改此 Python 代码以生成正确的输出吗？例如，如果输入 March，则输出“02”。目前，程序始终输出 00，表示一月，无论输入如何。这是代码:

x = raw_input("Starting Month: ")

if x == "January" or "january":
   stMonth = '00'
elif x == "February" or "february":
    stMonth = '01'
elif x == "March" or "march":
    stMonth = '02'
elif x == "April" or "april":
    stMonth = '03'
elif x == "May" or "may":
    stMonth = '04'
elif x == "June" or "june":
    stMonth = '05'
elif x == "July" or "june":
    stMonth = '06'
elif x == "August" or "august":
    stMonth = '07'
elif x == "September" or "september":
    stMonth = '08'
elif x == "October" or "october":
    stMonth = '09'
elif x == "November" or "november":
    stMonth = '10'
elif x == "December" or "december":
    stMonth = '11'
else:
    print "error"
print stMonth

---

输出:

$ python month.py 
Starting Month: march
00

提前致谢 - 非常非常感谢您的帮助!

Answer 1

因为 or优先级高于 == : x == 'january' or 'January'实际上与 (x == 'january') or 'January' 相同, 以及 'January'评估为 true ，组合语句始终为真。

您应该将每个语句更改为 x == 'january' or x == 'January' .