我正在使用递归神经网络，需要处理我的输入文本文件(包含树)以提取单词。 输入文件看起来像:
(3 (2 (2 The) (2 Rock)) (4 (3 (2 is) (4 (2 destined) (2 (2 (2 (2 (2 to) (2 (2 be) (2 (2 the) (2 (2 21st) (2 (2 (2 Century) (2 's)) (2 (3 new) (2 (2 ``) (2 Conan)))))))) (2 '')) (2 and)) (3 (2 that) (3 (2 he) (3 (2 's) (3 (2 going) (3 (2 to) (4 (3 (2 make) (3 (3 (2 a) (3 splash)) (2 (2 even) (3 greater)))) (2 (2 than) (2 (2 (2 (2 (1 (2 Arnold) (2 Schwarzenegger)) (2 ,)) (2 (2 Jean-Claud) (2 (2 Van) (2 Damme)))) (2 or)) (2 (2 Steven) (2 Segal))))))))))))) (2 .)))
(4 (4 (4 (2 The) (4 (3 gorgeously) (3 (2 elaborate) (2 continuation)))) (2 (2 (2 of) (2 ``)) (2 (2 The) (2 (2 (2 Lord) (2 (2 of) (2 (2 the) (2 Rings)))) (2 (2 '') (2 trilogy)))))) (2 (3 (2 (2 is) (2 (2 so) (2 huge))) (2 (2 that) (3 (2 (2 (2 a) (2 column)) (2 (2 of) (2 words))) (2 (2 (2 (2 can) (1 not)) (3 adequately)) (2 (2 describe) (2 (3 (2 (2 co-writer/director) (2 (2 Peter) (3 (2 Jackson) (2 's)))) (3 (2 expanded) (2 vision))) (2 (2 of) (2 (2 (2 J.R.R.) (2 (2 Tolkien) (2 's))) (2 Middle-earth))))))))) (2 .)))
作为输出，我希望新文本文件中的单词列表为:
The
Rock
is
destined
...
(忽略行与行之间的空格。)
我尝试在 python 中进行，但无法找到解决方案。另外，我读到 awk 可用于文本处理，但无法生成任何工作代码。感谢您的帮助。
最佳答案
你可以使用正则表达式!
import re
my_string = # your string from above
pattern = r"\(\d\s+('?\w+)"
results = re.findall(pattern, my_string)
print(results)
# ['The',
# 'Rock',
# 'is',
# 'destined',
# 'to',
# 'be',
# 'the',
# ...
请注意 re.findall将返回一个匹配列表，所以如果你想在一个句子中将它们全部打印出来，你可以使用:
' '.join(results)
或您想要用来分隔单词而不是空格的任何其他字符。
打破正则表达式模式我们有:
pattern = r"""
\( # match opening parenthesis
\d # match a number. If the numbers can be >9, use \d+
\s+ # match one or more white space characters
( # begin capturing group (only return stuff inside these parentheses)
'? # match zero or one apostrophes (so we don't miss posessives)
\w+ # match one or more text characters
) # end capture group
"""
关于python - 从文本文件中提取单词，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50765499/