我正在尝试解决这段代码中的错误:
import time
while1 = True
def grader (z):
if z >= 0 or z <= 59:
return "F"
elif z >= 60 or z <= 62:
return "D-"
elif z >= 62 or z <= 66:
return "D"
elif z >= 67 or z <= 69:
return "D+"
elif z >= 70 or z <= 62:
return "C-"
elif z >= 73 or z <= 76:
return "C"
elif z >= 77 or z <= 79:
return "C+"
elif z >= 80 or z <= 82:
return "B-"
elif z >= 83 or z <= 86:
return "B"
elif z >= 87 or z <= 89:
return "B+"
elif z >= 90 or z <= 92:
return "A-"
else:
return "A"
while while1:
z = int(input("I will tell you the grade of this number, enter from 1 - 100\n"))
if z < 0 or z > 100:
print "Between 1 and 100 PLEASE!\n"
while1 = True
print grader(z)
print "New number now\n"
time.sleep(100)
while1 = True
这种情况下的参数是整数z
。 z
的值由用户设置,然后该函数应确定 z
的字母等级值,尽管它始终返回“F”。
这让我很困惑(我是新手),我需要一些帮助。
最佳答案
你的问题是这样的:
if z >= 0 or z <= 59:
使用:
if 0 <= z <= 59:
这减轻了您在使用 or
而不是 and
时遇到的问题,并且更具可读性。
但是你应该看看bisect模块:
>>> def grade(score, breakpoints=[60, 70, 80, 90], grades='FDCBA'):
i = bisect(breakpoints, score)
return grades[i]
>>> [grade(score) for score in [33, 99, 77, 70, 89, 90, 100]]
['F', 'A', 'C', 'C', 'B', 'A', 'A']
关于Python整数到字母等级问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16907363/