我正在尝试弄清楚如何创建,例如,一个看起来像这样的字典:d[keys[0]][keys[1]][keys[2]]
来自这样的列表:keys = ["key1", "key2", "key3"]
...
我尝试了以下方法:
keys = ["key1", "key2", "key3"]
d = {}
d_ref= d
for key_num, key in enumerate(keys):
if key_num < len(keys)-1:
d[key] = {}
d_ref = d[key]
else:
d_ref[key] = []
print(d)
但结果是这样的:
{'key1': {}, 'key2': {'key3': []}}
我的目标是这个输出:
{'key1' : { 'key2' : { "key3": [] } }
更新
感谢 wim 的回答,让我得到了我想要的结果:
keys = ["key1", "key2", "key3"]
d = []
for key in reversed(keys):
d = {key: d}
print(d)
最佳答案
只需一个简单的 for 循环就可以解决问题
>>> d = {}
>>> for k in reversed(keys):
... d = {k: d}
...
>>> d
{'key1': {'key2': {'key3': {}}}}
(编辑: OP 在发布后更改了问题)如果您想要一个列表作为初始值,只需更改第一个分配:
>>> d = []
>>> for k in reversed(keys):
... d = {k: d}
...
>>> d
{'key1': {'key2': {'key3': []}}}
关于python - 将键列表转换为嵌套字典,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46368027/