我对表单中的字段渲染有疑问。我有这段代码:
class RTForm(forms.ModelForm):
type_options = {
'error': {
'label': _('Error'),
},
'warning': {
'label': _('Warning'),
},
'off': {
'label': _('Disable'),
}
}
choice_type = forms.ChoiceField(
choices=[(k, v['label']) for k, v in type_options.items()],
required=True, widget=forms.RadioSelect(
attrs={
class="choices"
}
)
)
class Meta:
model = RT
def __init__(self, *args, **kwargs):
self.rt = kwargs.pop('instance', None)
errors = create_error_list(rt.type)
warnings = create_warning_list(rt.type)
super(RTV, self).__init__(*args, **kwargs)
我想做的是在我的模板上拥有与初始化列表中返回的错误/警告数量一样多的 choice_type 字段(每次不同的数字)。那可能吗?我想不出可能的解决方案。
最佳答案
在您使用 type
( http://docs.python.org/2/library/functions.html#type ) 创建的动态类的帮助下,您的要求将成为可能
我不确定我是否正确理解了您问题的业务需求,但是我会在 View 中执行类似的操作以创建自定义表单:
choice_type = forms.ChoiceField( # this is your class
choices=[(k, v['label']) for k, v in type_options.items()],
required=True, widget=forms.RadioSelect(attrs={
class="choices"
})
)
# let's say that I want my custom form to have two choice fields:
formfields = {}
formfields['choice_field1']= choice_type
formfields['choice_field2']= choice_type
# Now I can create my custom class
form_class = type('CustomForm', (django.forms.Form,), formfields )
# Finally I will create an instance of my custom class
form = form_class()
# Ok ! form can be used in my view as any normal django form !!
关于python - 渲染表单字段随机时间,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19446013/