python - 返回特定字符串的按钮 [Tkinter]

Question

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Answer 1

这里是你如何做到的:

• 定义一个command对于循环中的每个按钮
• 将当前循环索引传递给回调(参见 How to pass arguments to a Button command in Tkinter?)
• 在按钮点击回调中，通过传入回调的索引从 namelist 中获取项目

代码如下:

from Tkinter import *


class display():
    def __init__(self, controlframe):
        self.controlframe = controlframe
        self.namelist = ["Mike", "Rachael", "Mark", "Miguel", "Peter", "Lyn"]

    def callback(self, index):
        print self.namelist[index]

    def showlist(self):
        self.frame = Frame(self.controlframe, height=1)
        self.frame.pack()
        row = 0
        for index, x in enumerate(self.namelist):
            label = Label(self.frame, text="%s " % x, width=17, anchor="w") #limit the name to 17 characters
            fooButton = Button(self.frame, text="Foo", 
                               command=lambda index=index: self.callback(index))
            label.grid(row=row, column=0, sticky="W")
            fooButton.grid(row=row, column=1)
            row = row + 1


tk = Tk()

D = display(tk)
D.showlist()
tk.mainloop()

注意索引是如何传递给 lambda 的，这就是所谓的“lambda 闭包范围”问题，请参阅 Python lambda closure scoping .

希望对您有所帮助。