我试图在每 3 秒更改一次的单个窗口中随机显示目录中的图像。我还希望它是跨平台的,因为我在 Windows 中开发,但它会在 linux 上运行。
目前我有这段工作代码可以用鼠标点击(下面的代码)遍历目录的所有图像文件
import os, sys, Tkinter, Image, ImageTk
def button_click_exit_mainloop (event):
event.widget.quit()
root = Tkinter.Tk()
root.bind("<Button>", button_click_exit_mainloop)
root.geometry('+%d+%d' % (-5,-5)) #controls where the window is
#gets list of file names in certain directory. In this case, the directory it is in
dirlist = os.listdir('.')
for f in dirlist:
try:
image1 = Image.open(f)
root.geometry('%dx%d' % (image1.size[0],image1.size[1]))
tkpi = ImageTk.PhotoImage(image1)
label_image = Tkinter.Label(root, image=tkpi)
label_image.place(x=0,y=0,width=image1.size[0],height=image1.size[1])
root.mainloop() # wait until user clicks the window
except Exception, e:
pass
然而,它执行此操作的方式是,当鼠标单击窗口时,它会调用一个函数来关闭小部件。
我遇到的问题是如何调用此函数,或在没有事件的情况下关闭小部件。有什么建议吗?
这是我目前拥有的。这显然不起作用,因为它卡在 root.mainloop() 中,但它显示了我的一般想法(下面的代码)
import os, sys, Tkinter, Image, ImageTk, random
root = Tkinter.Tk()
root.geometry('+%d+%d' % (-5,-5)) #controls where the window is
#gets list of file names in certain directory. In this case, the directory it is in
dirlist = os.listdir('.') #might not be in order, CHECK!!!
while True:
randInt = random.randint(0, 1)
image = Image.open(dirlist[randInt])
root.geometry('%dx%d' % (image.size[0],image.size[1]))
tkpi = ImageTk.PhotoImage(image)
label_image = Tkinter.Label(root, image=tkpi)
label_image.place(x=0,y=0,width=image.size[0],height=image.size[1])
root.mainloop()
time.sleep(3)
谢谢!
-乔纳森
编辑:对布莱恩奥克利的回应: 我尝试了您的建议,这看起来像是解决方案。
该函数每 3 秒调用一次,并且正在创建一个窗口,但图像没有放置在窗口中。
是不是我没有root权限?我如何获得访问权限?
这是我目前拥有的:
import os, sys, Tkinter, Image, ImageTk, random
def changeImage():
#gets list of file names in certain directory. In this case, the directory it is in
dirlist = os.listdir('.') #might not be in order, CHECK!!!
#get random image
randInt = random.randint(0, 1)
image = Image.open(dirlist[randInt])
#set size to show, in this case the whole picture
root.geometry('%dx%d' % (image.size[0],image.size[1]))
#Creates a Tkinter compatible photo image
tkpi = ImageTk.PhotoImage(image)
#Put image in a label and place it
label_image = Tkinter.Label(root, image=tkpi)
label_image.place(x=0,y=0,width=image.size[0],height=image.size[1])
# call this function again in three seconds
root.after(3000, changeImage)
root = Tkinter.Tk()
root.geometry('+%d+%d' % (-5,-5)) #controls where the window is
changeImage()
root.mainloop()
谢谢!!
解决方案编辑: 我没有更改代码,因此标签只创建一次,因此每次调用都会创建一个标签。我没有这样做是因为这可以应用于许多其他变量(例如 dirlist = os.listdir('.')),但会使代码更难阅读。除了可能使用更多周期外,我没有看到任何缺点?我没有看到内存随着时间的推移而增加,这对我来说很重要。
这是代码,谢谢 Bryan Oakley 对我的帮助!!
import os, Tkinter, Image, ImageTk, random
def changeImage():
global tkpi #need global so that the image does not get derefrenced out of function
#gets list of file names in certain directory. In this case, the directory it is in
dirlist = os.listdir('.')
#get random image
randInt = random.randint(0, 1)
image = Image.open(dirlist[randInt])
#set size to show, in this case the whole picture
root.geometry('%dx%d' % (image.size[0],image.size[1]))
#Creates a Tkinter compatible photo image
tkpi = ImageTk.PhotoImage(image)
#Put image in a label and place it
label_image = Tkinter.Label(root, image=tkpi)
label_image.place(x=0,y=0,width=image.size[0],height=image.size[1])
# call this function again in 1/2 a second
root.after(500, changeImage)
tkpi = None #create this global variable so that the image is not derefrenced
root = Tkinter.Tk()
root.geometry('+%d+%d' % (-5,-5)) #controls where the window is
changeImage()
root.mainloop()
最佳答案
您需要删除无限循环——tkinter 已经内置了一个。相反,使用 after
定期调用一个函数:
def changeImage():
<do whatever you want, such as swapping out images>
# call this function again in three seconds
root.after(3000, changeImage)
然后,在您的主程序中,您将在调用 mainloop
之前调用该函数:
root = Tkinter.Tk()
...
changeImage()
root.mainloop()
此外,您不需要 changeImage
每次都创建一个新的标签小部件——在函数外部创建一次标签,每次调用时只需更改图像。
关于python - 使用 Tkinter 在一个窗口中随机显示图像,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23569738/