python - 迭代并丢弃顺序重复项

Question

我是 python 的新手(任何类型的编码)。所以如果有点困惑我很抱歉

我有一个如下所示的 csv 文件

A    B     C              D        E            F         G      H
14  BP1 BP1-19119308    OR1A1   19119308    chip-chip   Hs578T  human   11/23/09 
15  BP1 BP1-19119308    PTPRE   19119308    chip-chip   Hs578T  human   11/23/09 
16  BP1 BP1-19119308    SELE    19119308    chip-chip   Hs578T  human   11/23/09 
17  BP1 BP1-19119308    TAC3    19119308    chip-chip   Hs578T  human   11/23/09 
18  BP1 BP1-19119308    VEGFA   19119308    chip-chip   Hs578T  human   11/23/09 
19  CHD7 CHD7-19251738  APOA1   19251738    chip-chip   MESC    mouse   11/23/09 
20  CHD7 CHD7-19251738  ARHGAP26 19251738   chip-chip   MESC    mouse  11/23/09

我需要让它看起来像这样

BP1-19119308-chip-chip-Hs578T-human OR1A1 PTPRE SELE TAC3 VEGFA 
CHD7-19251738-chip-chip-MESC-mouse  APOA1 ARHGAP26

我确实设法在第一列中使用了 C-F-G-H

import csv

out = open ('test.csv','rt', encoding='utf8') 
data =  csv.reader(out)
output = csv.writer(out) 

data = [row for row in data]
new_data = [[row[2]+'-'+row[5]+'-'+row[6] +'-'+ row[7], row[3]] for row in data] 

print (new_data)

out = open('new_data.csv','wt') 
output = csv.writer(out)  

for row in new_data:
   output.writerow(row)    

out.close()





A                                  B
BP1-19119308-chip-chip-Hs578T-human OR1A1
BP1-19119308-chip-chip-Hs578T-human PTPRE
BP1-19119308-chip-chip-Hs578T-human SELE
BP1-19119308-chip-chip-Hs578T-human TAC3
BP1-19119308-chip-chip-Hs578T-human VEGFA
CHD7-19251738-chip-chip-MESC-mouse  APOA1
CHD7-19251738-chip-chip-MESC-mouse  ARHGAP26
CHD7-19251738-chip-chip-MESC-mouse  ATP11A

但现在我在 A 中有这些重复项，但我不知道如何删除它们并转置 B 中分配给这些重复项的所有值。

我尝试再次循环以将当前值与先前值进行比较，但我把整个事情搞砸了。

有什么建议吗？

Answer 1

您想使用字典。如果您正在进行进一步分析，请将聚合值保存在每个标识符的列表中。您的标识符字符串是一个键，在每个键下，您都有一个值列表。

new_keys = [row[2] + '-' + row[5] + '-' + row[6] + '-' + row[7] for row in data] 
new_values = [row[3] for row in data]

aggregate_values = {} # An empty dictionary
# Iterate across the paired lists together
for key, value in zip(new_keys, new_values): 
    if key not in aggregate_values:
        aggregate_values[key] = [value]
    else: 
        aggregate_values[key].append(value)

# printed output
for key in aggregate_values:
    print key + " " + " ".join(aggregate_values[key])