python - 具体正则表达式搜索python

Question

这是我的第一篇文章。 当涉及到代码时，我总是来这个论坛寻找答案。

我一直在努力理解 Python 中的正则表达式，但这有点困难。

我有这样的文字:

Name:   Clash1
Distance:   -1.341m
Image Location: Test 1_navis_files\cd000001.jpg
HardStatus: New
Clash Point:    3.884m, -2.474m, 2.659m
Date Created:   2016/6/2422:45:09

Item 1
GUID:   6efaec51-b699-4d5a-b947-505a69c31d52
Path:   File ->Colisiones_v2015.dwfx ->Segment ->Pipes (1) ->Pipe Types (1) ->Default (1) ->Pipe Types [2463] ->Shell
Item Name:  Pipe Types [2463]
Item Type:  Shell

Item 2
GUID:   6efaec51-b699-4d5a-b947-505a69c31dea
Path:   File ->Colisiones_v2015.dwfx ->Segment ->Walls (4) ->Basic Wall (4) ->Wall 1 (4) ->Basic Wall [2343] ->Shell
Item Name:  Basic Wall [2343]
Item Type:  Shell

------------------


Name:   Clash2
Distance:   -1.341m
Image Location: Test 1_navis_files\cd000002.jpg
HardStatus: New
Clash Point:    3.884m, 3.533m, 2.659m
Date Created:   2016/6/2422:45:09

Item 1
GUID:   6efaec51-b699-4d5a-b947-505a69c31d52
Path:   File ->Colisiones_v2015.dwfx ->Segment ->Pipes (1) ->Pipe Types (1) ->Default (1) ->Pipe Types [2463] ->Shell
Item Name:  Pipe Types [2463]
Item Type:  Shell

Item 2
GUID:   6efaec51-b699-4d5a-b947-505a69c31de8
Path:   File ->Colisiones_v2015.dwfx ->Segment ->Walls (4) ->Basic Wall (4) ->Wall 1 (4) ->Basic Wall [2341] ->Shell
Item Name:  Basic Wall [2341]
Item Type:  Shell

------------------

我需要做的是创建一个列表来提取每个文本 block (由 分隔-------------------- --------) 以下内容作为字符串:冲突名称和冲突点。

例如:冲突 1 3.884、3.533、2.659

本人初学Python，对正则表达式了解不多。

谁能给我一些关于使用正则表达式从文本中提取这些值的线索？

我做了这样的事情:

exp = r'(?<=Clash Point\s)(?<=Point\s)([0-9]*)'
match = re.findall(exp, html)

if match:
    OUT.append(match)
else:
    OUT = 'fail'

但我知道我离我的目标还很远。

Answer 1

如果您正在寻找正则表达式解决方案，您可以想出:

^Name:\s*         # look for Name:, followed by whitespaces
                  # at the beginning of a line
(?P<name>.+)      # capture the rest of the line
                  # in a group called "name"
[\s\S]+?          # anything afterwards lazily
^Clash\ Point:\s* # same construct as above
(?P<point>.+)     # same as the other group

参见 a demo on regex101.com .

---

翻译成 Python 代码，这将是:

import re
rx = re.compile(r"""
                ^Name:\s*
                (?P<name>.+)
                [\s\S]+?
                ^Clash\ Point:\s*
                (?P<point>.+)""", re.VERBOSE|re.MULTILINE)

for match in rx.finditer(your_string_here):
    print match.group('name')
    print match.group('point')

这将输出:

Clash1
3.884m, -2.474m, 2.659m
Clash2
3.884m, 3.533m, 2.659m

参见 a working demo on ideone.com .