python - 如何使用python从csv中的同一列拆分日期和时间？

Question

我在 csv 文件中有第一列 (PERIOD_START_TIME)，其中包含日期和时间，但我需要将它们分成两个不同的列(日期、时间)，所以我需要你的帮助...

PERIOD_START_TIME   
01.31.2017 13:00:00  
01.31.2017 14:00:00  
01.31.2017 15:00:00  
01.31.2017 16:00:00  
01.31.2017 17:00:00  
01.31.2017 18:00:00  
01.31.2017 19:00:00  
01.31.2017 20:00:00  
01.31.2017 21:00:00  
01.31.2017 22:00:00  
01.31.2017 23:00:00  
02.01.2017 00:00:00  
02.01.2017 01:00:00  
02.01.2017 02:00:00  
02.01.2017 03:00:00  

Answer 1

您的PERIOD_START_TIME 可能不是日期时间。以确保它是。

df['PERIOD_START_TIME'] = pd.to_datetime(df['PERIOD_START_TIME'])

通过 dt 访问器访问 date 和 time 属性。

df['date'] = df.PERIOD_START_TIME.dt.date
df['time'] = df.PERIOD_START_TIME.dt.time

print(df)

     PERIOD_START_TIME        date      time
0  2017-01-31 13:00:00  2017-01-31  13:00:00
1  2017-01-31 14:00:00  2017-01-31  14:00:00
2  2017-01-31 15:00:00  2017-01-31  15:00:00
3  2017-01-31 16:00:00  2017-01-31  16:00:00
4  2017-01-31 17:00:00  2017-01-31  17:00:00
5  2017-01-31 18:00:00  2017-01-31  18:00:00
6  2017-01-31 19:00:00  2017-01-31  19:00:00
7  2017-01-31 20:00:00  2017-01-31  20:00:00
8  2017-01-31 21:00:00  2017-01-31  21:00:00
9  2017-01-31 22:00:00  2017-01-31  22:00:00
10 2017-01-31 23:00:00  2017-01-31  23:00:00
11 2017-02-01 00:00:00  2017-02-01  00:00:00
12 2017-02-01 01:00:00  2017-02-01  01:00:00
13 2017-02-01 02:00:00  2017-02-01  02:00:00
14 2017-02-01 03:00:00  2017-02-01  03:00:00

设置

import pandas as pd
from io import StringIO

txt = """PERIOD_START_TIME
01.31.2017 13:00:00  
01.31.2017 14:00:00  
01.31.2017 15:00:00  
01.31.2017 16:00:00  
01.31.2017 17:00:00  
01.31.2017 18:00:00  
01.31.2017 19:00:00  
01.31.2017 20:00:00  
01.31.2017 21:00:00  
01.31.2017 22:00:00  
01.31.2017 23:00:00  
02.01.2017 00:00:00  
02.01.2017 01:00:00  
02.01.2017 02:00:00  
02.01.2017 03:00:00  """

df = pd.read_csv(StringIO(txt), parse_dates=[0])