我有3个文件文件夹,我需要将folder1和folder2中的文件一个一个比较,然后将不同的结果一个一个写入到folder3中的文件中。现在我有这样的脚本:
import os
import difflib
import sys
path1 = "D:\folder1"
path2 = "D:\folder2"
path3 = "D:\folder3"
dirs1 = os.listdir(path1)
dirs2 = os.listdir(path2)
dirs3 = os.listdir(path3)
for file_name in dirs1:
file_1_path = os.path.join(path1, file_name)
name,ext = os.path.splitext(file_name)
file_2_path = os.path.join(path2, name+str(1)+ext)
file_3_path = os.path.join(path3, name+str('-Result')+ext)
with open (file_1_path) as xmlfile1:
with open (file_2_path) as xmlfile2:
line_num1=sum(1 for line1 in xmlfile1)
line_num2=sum(1 for line2 in xmlfile2)
xmlfile1.seek(0)
xmlfile2.seek(0)
diffInstance = difflib.Differ()
diffList = list(diffInstance.compare(xmlfile1.readlines(), xmlfile2.readlines()))
with open (file_3_path) as result:
for i,line in enumerate(diffList):
result.write(line)
if line_num1 == line_num2:
if line.startswith('+'):
sys.stdout.write('Current version Line: {} , text: {}'.format(i-1,line))
elif line.startswith('-'):
sys.stdout.write('Previous version Line: {}, text: {}'.format(i+1,line))
if line_num1 > line_num2:
x = line_num1-line_num2
if line.startswith('-'):
sys.stdout.write('Missed Line: {} from previous version, text: {}'.format(i+1,line))
if line_num1<line_num2:
y = line_num2-line_num1
if line.startswith('+'):
sys.stdout.write('Extra Line: {} in currect version, text: {}'.format(i+1,line))
但似乎效果不佳,我得到了这样的错误:
Traceback (most recent call last):
File "C:/comparison.py", line 25, in <module>
result.write(line)
io.UnsupportedOperation: not writable
最佳答案
仅使用一个参数的 open
假定 r
模式,您使用 with open (file_3_path) 作为结果:
。自然地,在读取模式下对文件对象使用 write
是行不通的。将其更改为 with open (file_3_path, 'w') as result:
并且文件将是可写的。在上下文中:
import os
import difflib
import sys
path1 = "D:\folder1"
path2 = "D:\folder2"
path3 = "D:\folder3"
dirs1 = os.listdir(path1)
dirs2 = os.listdir(path2)
dirs3 = os.listdir(path3)
for file_name in dirs1:
file_1_path = os.path.join(path1, file_name)
name,ext = os.path.splitext(file_name)
file_2_path = os.path.join(path2, name+str(1)+ext)
file_3_path = os.path.join(path3, name+str('-Result')+ext)
with open (file_1_path) as xmlfile1:
with open (file_2_path) as xmlfile2:
line_num1=sum(1 for line1 in xmlfile1)
line_num2=sum(1 for line2 in xmlfile2)
xmlfile1.seek(0)
xmlfile2.seek(0)
diffInstance = difflib.Differ()
diffList = list(diffInstance.compare(xmlfile1.readlines(), xmlfile2.readlines()))
with open (file_3_path, 'w') as result:
for i,line in enumerate(diffList):
result.write(line)
if line_num1 == line_num2:
if line.startswith('+'):
sys.stdout.write('Current version Line: {} , text: {}'.format(i-1,line))
elif line.startswith('-'):
sys.stdout.write('Previous version Line: {}, text: {}'.format(i+1,line))
if line_num1 > line_num2:
x = line_num1-line_num2
if line.startswith('-'):
sys.stdout.write('Missed Line: {} from previous version, text: {}'.format(i+1,line))
if line_num1<line_num2:
y = line_num2-line_num1
if line.startswith('+'):
sys.stdout.write('Extra Line: {} in currect version, text: {}'.format(i+1,line))
关于Python - 多个文件比较后,将结果写入多个文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43906120/