我正在尝试从两个抓取数据数组创建字典。此代码中的所有内容都有效,除了最后一步,它抛出以下错误:
--------------------------------------------------------------------------- TypeError Traceback (most recent call last) in () 19 tale_data_governors = [data.string for data in table_data_governors] 20 ---> 21 dictionary = dict(zip(table_data_governors,table_data))
TypeError: 'list' object is not callable
#Return the results in dictionary form
#{'Brown': 56.0126582278481, 'Whitman': 43.9873417721519}
html = requests.get("https://www.realclearpolitics.com/epolls/2010/governor/ca/california_governor_whitman_vs_brown-1113.html").text
soup = BeautifulSoup(html, 'html.parser')
#Scrape the percentage Numbers
table = soup.find_all('table')[0]
table_row = table.find_all('tr')[1]
table_data = table_row.find_all('td')[3:5]
#Scrape the Names
table_row_governors = table.find_all('tr')[0]
table_data_governors = table_row_governors.find_all('th')[3:5]
table_data_governors
table_data = [data.string for data in table_data]
tale_data_governors = [data.string for data in table_data_governors]
dictionary = dict(zip(table_data_governors,table_data))
如有任何帮助/建议,我们将不胜感激!
谢谢
编辑:我认为这可能与此有关:
[(<th>Brown (D)</th>, u'53.1'), (<th>Whitman (R)</th>, u'41.7')]
这是调用 zip() 时得到的元组数组。我不太清楚为什么会这样。我以为 data.string 会将这些转换成字符串..
编辑 2:此代码有效
a = zip(table_data, table_data_governors)
b = {}
for x,y in a:
b[y] = x
b
奇怪的东西。可能与 Ipython 笔记本有关。
最佳答案
您的代码中有错别字。
您已定义 tale_data_governors
并稍后调用 table_data_governors
。
关于python - 用抓取的值创建字典(Beautiful Soup Python),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45086945/