下午好
我已经尝试解决这个问题一段时间了,我们将不胜感激。
这是我的数据框:
Channel state rfq_qty
A Done 10
B Tied Done 10
C Done 10
C Done 10
C Done 10
C Tied Done 10
B Done 10
B Done 10
I would like to:
- Group by channel, then state
- Sum the rfq_qty for each channel
- Count the occurences of each 'done' string in state ('Done' is treated the same as 'Tied Done' i.e. anything with 'done' in it)
- Display the channels rfq_qty as a percentage of the total number of rfq_qty (80)
Channel state rfq_qty Percentage
A 1 10 0.125
B 3 30 0.375
C 4 40 0.5
I have attempted this with the following:
df_Done = df[
(
df['state']=='Done'
)
|
(
df['state'] == 'Tied Done'
)
][['Channel','state','rfq_qty']]
df_Done['Percentage_Qty']= df_Done['rfq_qty']/df_Done['rfq_qty'].sum()
df_Done['Done_Trades']= df_Done['state'].count()
display(
df_Done[
(df_Done['Channel'] != 0)
].groupby(['Channel'])['Channel','Count of Done','rfq_qty','Percentage_Qty'].sum().sort_values(['rfq_qty'], ascending=False)
)
Works but looks convoluted. Any improvements?
最佳答案
我认为你可以使用:
- 首先按
isin
过滤和loc
-
groupby
并按agg
聚合带有新列名和函数的元组 - 添加
百分比
除以div
和总和
- 必要时最后
sort_values
通过rfq_qty
df_Done = df.loc[df['state'].isin(['Done', 'Tied Done']), ['Channel','state','rfq_qty']]
#if want filter all values contains Done
#df_Done = df[df['state'].str.contains('Done')]
#if necessary filter out Channel == 0
#mask = (df['Channel'] != 0) & df['state'].isin(['Done', 'Tied Done'])
#df_Done = df.loc[mask, ['Channel','state','rfq_qty']]
d = {('rfq_qty', 'sum'), ('Done_Trades','size')}
df = df_Done.groupby('Channel')['rfq_qty'].agg(d).reset_index()
df['Percentage'] = df['rfq_qty'].div(df['rfq_qty'].sum())
df = df.sort_values('rfq_qty')
print (df)
Channel Done_Trades rfq_qty Percentage
0 A 1 10 0.125
1 B 3 30 0.375
2 C 4 40 0.500
关于python - 根据自定义函数聚合数据框中的多列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49272452/