我想根据前面的标签选择元素的内容:
<h4>Models & Products</h4>
<div class="profile-area">...</div>
<h4>Production Capacity (year)</h4>
<div class="profile-area">...</div>
如何根据前面标签的内容得到“profile-area”的值？
这是我的代码:
import requests
from bs4 import BeautifulSoup
import csv
import re
html_doc = """
<html>
<body>
<div class="col-md-6">
<iframe class="factory_detail_google_map" frameborder="0" src=
"https://www.google.com/maps/embed/v1/search?q=3.037787%2C101.38189&key=AIzaSyCMDADp9QHYbQ8OBGl8puAOv-16W8ziz7Y"
allowfullscreen=""></iframe>
</div>
<div class="col-md-12">
<h4>Models & Products</h4>
<div class="profile-area">
Large Buses, Trucks, Trailer-heads
</div>
<h4>Production Capacity (year)</h4>
<div class="profile-area">
Vehicle 700 units /year
</div>
<h4>Output</h4>
<div class="profile-area">
Vehicle 356 units ( 2016 )
</div>
<div class="profile-area">
Vehicle 477 units ( 2015 )
</div>
<div class="profile-area">
Vehicle 760 units ( 2014 )
</div>
<div class="profile-area">
Vehicle 647 units ( 2013 )
</div>
</div>
</body>
</html>
"""
soup = BeautifulSoup(html, 'lxml')
#link=soup.iframe.get('src')
#print(link.split("%2C"))
for item in soup.select("div.profile-area"):
print(item.text)
如您所见，我也在尝试将 Google map 链接拆分为坐标，但这可能需要我自己解决。
感谢您的帮助!
最佳答案
使用 .find_previous_sibling() 显式查找前面的第一个 h4 标记:
for item in soup.select("div.profile-area"):
prev_h4 = item.find_previous_sibling('h4').text
if 'Capacity' in prev_h4:
print(item.text)
输出
Vehicle 700 units /year
关于python - BeautifulSoup:根据前面标签的内容打印 div，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50589151/