问题:
您好，现在我正在查询 sqlite 并将结果分配给这样的变量:
表结构:rowid，name，something
cursor.execute("SELECT * FROM my_table WHERE my_condition = 'ExampleForSO'")
found_record = cursor.fetchone()
record_id = found_record[0]
record_name = found_record[1]
record_something = found_record[2]
print(record_name)
但是，很有可能有一天我必须向表中添加一个新列。让我们以添加该列为例:
表结构:rowid,age,name,something
在那种情况下，如果我们运行相同的代码，name 和 something 将被错误地分配，并且打印不会给我名字而是年龄，所以我必须手动编辑代码以适应当前索引。但是，我现在正在为一个复杂的 UI 使用包含 100 多个字段的表格，这样做很烦人。
期望的输出:
我想知道是否有更好的方法通过使用字典或类似的东西来捕获结果:
Note for lurkers: The next snipped is made up code that does not works, do not use it.
cursor.execute_to(my_dict,
'''SELECT rowid as my_dict["id"],
name as my_dict["name"],
something as my_dict["something"]
FROM my_table WHERE my_condition = "ExampleForSO"''')
print(my_dict['name'])
我可能对这种方法有误，但这接近我想要的。这样，如果我不将结果作为索引访问，并且如果添加一个新列，无论它在哪里，输出都是相同的。
实现它的正确方法是什么？还有其他选择吗？
可以使用namedtuple，然后在sqlite中指定connection.row_factory。示例:
import sqlite3
from collections import namedtuple
# specify my row structure using namedtuple
MyRecord = namedtuple('MyRecord', 'record_id record_name record_something')
con = sqlite3.connect(":memory:")
con.isolation_level = None
con.row_factory = lambda cursor, row: MyRecord(*row)
cur = con.cursor()
cur.execute("CREATE TABLE my_table (record_id integer PRIMARY KEY, record_name text NOT NULL, record_something text NOT NULL)")
cur.execute("INSERT INTO my_table (record_name, record_something) VALUES (?, ?)", ('Andrej', 'This is something'))
cur.execute("INSERT INTO my_table (record_name, record_something) VALUES (?, ?)", ('Andrej', 'This is something too'))
cur.execute("INSERT INTO my_table (record_name, record_something) VALUES (?, ?)", ('Adrika', 'This is new!'))
for row in cur.execute("SELECT * FROM my_table WHERE record_name LIKE 'A%'"):
print(f'ID={row.record_id} NAME={row.record_name} SOMETHING={row.record_something}')
con.close()
打印:
ID=1 NAME=Andrej SOMETHING=This is something
ID=2 NAME=Andrej SOMETHING=This is something too
ID=3 NAME=Adrika SOMETHING=This is new!