python - 如何从 image.pixel 中找到像素位置？

Question

所以，我有这个有效的脚本，它打印出所有具有和 rgb 值 (102,102,102) 的像素，但我不知道我现在如何能够获得该像素位置并单击它......任何建议？

编辑:像素位置是指像素 x,y 坐标

import pyautogui
import time
from PIL import Image
import mss
import mss.tools
import cv2
import numpy as np
from PIL import ImageGrab
import colorsys


time.sleep(3)


def shootfunc(xc, yc):
    pyautogui.click(xc, yc)

gameregion = [71, 378, 328, 530]

foundpxl = 0

xx = 0
while xx <= 300:
    with mss.mss() as sct:
        region = {'top': 0, 'left': 0, 'width': 1920, 'height': 1080}
        imgg = sct.grab(region)
        pxls = imgg.pixels


        for pxl in pxls:
            for pxll in pxl:
                if pxll == (102, 102, 102) or pxl == "(255, 255, 255)" or pxl == [255, 255, 255]:
                    foundpxl = pxll
                    print(foundpxl)
        xx = xx + 1
        time.sleep(.1)

Answer 1

您可以 enumerate您迭代的任何序列。这将返回元素和元素的索引:

>>> for i, e in enumerate('abc'):
...     print(i, e)
0 a
1 b
2 c

因此，您可以利用它来查找像素的行和列:

for row, pxl in enumerate(pxls):
    for col, pxll in enumerate(pxl):
        ...