python - 将宽变长但重复特定列

Question

我有一个如下所示的数据框

df2 = pd.DataFrame({'pid':[1,2,3,4],'BP1Date':['12/11/2016','12/21/2016','12/31/2026',np.nan],'BP1di':[21,24,25,np.nan],'BP1sy':[123,125,127,np.nan],'BP2Date':['12/31/2016','12/31/2016','12/31/2016','12/31/2016'],'BP2di':[21,26,28,30],'BP2sy':[123,130,135,145],
                   'BP3Date':['12/31/2017','12/31/2018','12/31/2019','12/31/2116'],'BP3di':[21,31,36,np.nan],'BP3sy':[123,126,145,np.nan]})

如下图所示

我希望我的输出如下所示

这是我根据其他帖子的 SO 建议尝试的，但我无法产生或接近预期的输出

df = pd.melt(df2, id_vars='pid', var_name='col', value_name='dates')
df['col2'] = [x.split("Date")[0][:3] for x in df['col']]
df = df[df.groupby(['pid','col2'])['dates'].transform('count').ne(0)].copy()
df['col3'] = df['col2'].str.extract('(\d+)', expand=True).astype(int)
df2 = df.sort_values(by=['pid','col3'])

请注意两点

a) 对于每个日期，我有两个读数 (BP{n}di, BP{n}si)

b) 我只想在 所有 3 列 一起为 NA 时删除 NA 记录(在这种情况下，pid = 4、BP1Date、BP1di、BP1sy 为 NA)。如果任何列不是 NA，则应保留 NA，如下所示。因此我没有使用 stack(dropna=False) 而是使用基于 SO 帖子的 pd.melt

如何转换输入以获得如上图所示的输出？

根据回答评论更新了屏幕截图

Answer 1

将 lreshape 与 DataFrame.stack 一起使用对于 reshape ，然后按 Date 列删除缺失值 DataFrame.dropna并按前 3 列排序:

a = [col for col in df2.columns if col.endswith('Date')]
b = [col for col in df2.columns if col.endswith('di')]
c = [col for col in df2.columns if col.endswith('sy')]

df1 = (pd.lreshape(df2, {'Date':a, 'di':b, 'sy':c}, dropna=False)
       .set_index(['pid','Date'])
       .stack(dropna=False)
       .rename_axis(['pid','Date','type'])
       .reset_index(name='value')
       .dropna(subset=['Date'])
       .assign(Date = lambda x: pd.to_datetime(x['Date'], dayfirst=True))
       .sort_values(['pid','Date','type'])
       .reset_index(drop=True)
       )

---

print (df1)
    pid       Date type  value
0     1 2016-11-12   di   21.0
1     1 2016-11-12   sy  123.0
2     1 2016-12-31   di   21.0
3     1 2016-12-31   sy  123.0
4     1 2017-12-31   di   21.0
5     1 2017-12-31   sy  123.0
6     2 2016-12-21   di   24.0
7     2 2016-12-21   sy  125.0
8     2 2016-12-31   di   26.0
9     2 2016-12-31   sy  130.0
10    2 2018-12-31   di   31.0
11    2 2018-12-31   sy  126.0
12    3 2016-12-31   di   28.0
13    3 2016-12-31   sy  135.0
14    3 2019-12-31   di   36.0
15    3 2019-12-31   sy  145.0
16    3 2026-12-31   di   25.0
17    3 2026-12-31   sy  127.0
18    4 2016-12-31   di   30.0
19    4 2016-12-31   sy  145.0
20    4 2116-12-31   di    NaN
21    4 2116-12-31   sy    NaN

替代解决方案是在 Series.str.extract 创建的列中使用 MultiIndex和 MultiIndex.from_tuples :

df2 = df2.set_index('pid')

c = df2.columns.to_frame(name='orig')
c = c['orig'].str.extract('(.+)(Date|di|sy)').apply(tuple, 1)

df2.columns = pd.MultiIndex.from_tuples(c)

df1 = (df2.stack(0)
       .set_index(['Date'], append=True)
       .reset_index(level=1, drop=True)
       .stack(dropna=False)
       .rename_axis(['pid','Date','type'])
       .reset_index(name='value')
       .dropna(subset=['Date'])
       .assign(Date = lambda x: pd.to_datetime(x['Date'], dayfirst=True))
       .sort_values(['pid','Date','type'])
       .reset_index(drop=True)
       )

---

print (df1)
    pid       Date type  value
0     1 2016-11-12   di   21.0
1     1 2016-11-12   sy  123.0
2     1 2016-12-31   di   21.0
3     1 2016-12-31   sy  123.0
4     1 2017-12-31   di   21.0
5     1 2017-12-31   sy  123.0
6     2 2016-12-21   di   24.0
7     2 2016-12-21   sy  125.0
8     2 2016-12-31   di   26.0
9     2 2016-12-31   sy  130.0
10    2 2018-12-31   di   31.0
11    2 2018-12-31   sy  126.0
12    3 2016-12-31   di   28.0
13    3 2016-12-31   sy  135.0
14    3 2019-12-31   di   36.0
15    3 2019-12-31   sy  145.0
16    3 2026-12-31   di   25.0
17    3 2026-12-31   sy  127.0
18    4 2016-12-31   di   30.0
19    4 2016-12-31   sy  145.0
20    4 2116-12-31   di    NaN
21    4 2116-12-31   sy    NaN