python - 使用 Django/Twilio 进行条件短信响应

Question

我尝试根据不同的参数(来电显示、文本正文)调整短信响应，错误是“HTTP 检索失败” 我尝试过针对不同的调用者使用 Flask 教程:

def hello_monkey():
    """Respond and greet the caller by name."""

    from_number = request.values.get('From', None)
    if from_number in callers:
        message = callers[from_number] + ", thanks for the message!"
    else:
        message = "Monkey, thanks for the message!"

但我意识到 Django 可能有所不同，所以我尝试了这些和其他几个:

def hello_monkey(request, From)
    #with    
    from = From

def hello_monkey(request):
    #with
    number = request.POST["Body"]

谢谢 编辑:忘记了link

Answer 1

实际上在 Django 中它会非常相似，你应该阅读更多关于 request 的内容。 。由于您不知道请求是 POST 还是 GET，因此可以使用 HttpRequest.REQUEST:

callers = {
    "+14158675309": "Curious George",
    "+14158675310": "Boots",
    "+14158675311": "Virgil",
}

def hello_monkey(request):
    """Respond and greet the caller by name."""

    from_number = request.REQUEST.get('From', None)
    if from_number in callers:
        message = callers[from_number] + ", thanks for the message!"
    else:
        message = "Monkey, thanks for the message!"

    # .... your code ....

希望对你有帮助!