元组的按元素相加相当简单:
a = (1,2,3,4)
b = (2,4,6,8)
tuple(x+y for x,y in zip(a,b))
(3,6,9,12)
但是嵌套元组的逐元素加法更加复杂:
a = ((1,2),(3,4),(5,6))
b = ((2,4),(6,8),(10,12))
tuple(x+y for tup_a, tup_b in zip(a,b) for x,y in zip(tup_a,tup_b))
(3,6,9,12,15,18)
元组被展平。如何在保留元组结构的同时对固定元组执行元素加法?
这是所需的输出:
((3,6),(9,12),(15,18))
最佳答案
嵌套生成器表达式:
tuple(tuple(x + y for x, y in zip(tup_a, tup_b)) for tup_a, tup_b in zip(a, b))
演示:
>>> a = ((1,2),(3,4),(5,6))
>>> b = ((2,4),(6,8),(10,12))
>>> tuple(tuple(x + y for x, y in zip(tup_a, tup_b)) for tup_a, tup_b in zip(a, b))
((3, 6), (9, 12), (15, 18))
关于python - python 中嵌套元组的元素明智操作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19470454/