python - 从 Tornado Python 中的 RequestHandler 访问 URL

Question

在我的 super 简单 Tornado URL 调度程序中:

import tornado.ioloop
import tornado.web

class MainHandler(tornado.web.RequestHandler):
    def get(self):
        self.write("Main MainHandler ")

class MainHandler1(tornado.web.RequestHandler):
    def get(self):
        self.write("Main MainHandler 1")

class api_v1(tornado.web.RequestHandler):
    def get(self):
        pass


if __name__ == "__main__":
    application = tornado.web.Application(handlers=[
        (r"/", MainHandler),
        (r"/main1/", MainHandler1),
        #Meta API from the Application URIs
        (r"/api/v1/", api_v1),
    ])


    application.listen(8888)
    tornado.ioloop.IOLoop.instance().start()

如何从class api_v1(tornado.web.RequestHandler)访问handlers变量。有可能吗？

我想在用户访问http://.../api/v1/时显示URLS模式

提前致谢。

Answer 1

传递到 Application 构造函数的处理程序表在事后不可用。相反，请在创建应用程序之前保存一份副本并将其提供给您的处理程序:

handlers = [...]
# Unrecognized keyword arguments end up in Application.settings; recognized ones
# get eaten.  Pass the handler table in twice, once for the Application itself
# and once for settings.
app = Application(handlers, handler_table=handlers)

并在处理程序中使用self.settings['handler_table']