python - 如何正确打破这个循环

Question

我对如何解决以下问题有点迷失。 当 xxxx 计数器达到 15 时，我希望脚本停止，这工作正常。 但是，当其中一个 try 语句出现错误时，我只希望它转到 oldlist 中的下一个 url，而不是像现在一样停止脚本。

我阅读了有关此内容的文档以及可能更好地包含 While 语句，但我不确定在这里要做什么才能使其像我希望的那样工作。它实际上是一个更大的循环，但只是在下面进行了简化。

系统:Python 2.7.* x64 上的 IDLE

xxxx = 0
oldlist = [lost of stuff]
newlist = [lots of stuff]
otherlist = [lots of stuff]

for url in oldlist:
    found = False

    if xxxx == 15:
        break

    for item in newlist:
        if something:
            if something:
                found = True

    for items in otherlist:
        if something:
            found = False

    if found == True:
        xxxx +=1

        try:
            something
        except Exception as thing: #catch em all
            print "1st Error"
            break    #should go to the next url

        try:
            something
        except Exception as morethings: #catch em all
            print "2nd Error"
            break    #should go to the next url

这真的是糟糕的Python吗？ 它应该更像是:

while xxxx != 15:
    for url in oldlist:
        found = False

        for item in newlist:
            if something:
                if something:
                    found = True

        for items in otherlist:
            if something:
                found = False

        while found == True:
            xxxx +=1

        while True:
            try:
                something
            except Exception as thing: #catch em all
                print "1st Error"
                break

            try:
                something
            except Exception as morethings: #catch em all
                print "2nd Error"
                break

Answer 1

如果我理解您的问题，您需要 continue 语句，而不是 break 语句。

Flow-control docs