python - 列表查找中部分字符串匹配的单行代码

Question

是否有更简单的方法来执行以下操作？

filename = 'vudu_hail_20140101.xml'
acceptable_stems = ['vudu', 'google']

process_file = False
for acceptable_stem in acceptable_stems:
    if acceptable_stem in filename:
        process_file = True

基本上，我正在寻找一个 bool 决定因素来判断文件名中是否包含某个词干。这如何用一行代码来完成？

Answer 1

使用 any 怎么样？关键字:

any([acceptable_stem in filename for acceptable_stem in acceptable_stems])

示例:

>> filename = 'vudu_hail_20140101.xml'
>> acceptable_stems = ['vudu', 'google']
>> any([acceptable_stem in filename for acceptable_stem in acceptable_stems])
True

>> filename = 'vudu_hail_20140101.xml'
>> acceptable_stems = ['vuduf', 'google']
>> any([acceptable_stem in filename for acceptable_stem in acceptable_stems])
False