python - 缩进错误 : unexpected unindent can't find the issue

Question

这是完整的代码

from itertools import imap
import threading
import time
import hashlib
import sys

__b58chars = '123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
__b58base = len(__b58chars)

global PUBKEY_ADDRESS
global SCRIPT_ADDRESS
PUBKEY_ADDRESS = 12
SCRIPT_ADDRESS = 8

def rev_hex(s):
    return s.decode('hex')[::-1].encode('hex')


def int_to_hex(i, length=1):
    s = hex(i)[2:].rstrip('L')
    s = "0"*(2*length - len(s)) + s
    return rev_hex(s)


def var_int(i):
    if i < 0xfd:
        return int_to_hex(i)
    elif i <= 0xffff:
        return "fd" + int_to_hex(i, 2)
    elif i <= 0xffffffff:
        return "fe" + int_to_hex(i, 4)
    else:
        return "ff" + int_to_hex(i, 8)


Hash = lambda x: hashlib.sha256(hashlib.sha256(x).digest()).digest()


hash_encode = lambda x: x[::-1].encode('hex')


hash_decode = lambda x: x.decode('hex')[::-1]


def header_to_string(res):
    pbh = res.get('prev_block_hash')
    if pbh is None:
        pbh = '0'*64

    return int_to_hex(res.get('version'), 4) \
        + rev_hex(pbh) \
        + rev_hex(res.get('merkle_root')) \
        + int_to_hex(int(res.get('timestamp')), 4) \
        + int_to_hex(int(res.get('bits')), 4) \
        + int_to_hex(int(res.get('nonce')), 4) \
        + int_to_hex(int(res.get('BirthdayA')), 4) \ # this is where it says the error is
        + int_to_hex(int(res.get('BirthdayB')), 4)

def hex_to_int(s):
    return int('0x' + s[::-1].encode('hex'), 16)


def header_from_string(s):
    return {
        'version': hex_to_int(s[0:4]),
        'prev_block_hash': hash_encode(s[4:36]),
        'merkle_root': hash_encode(s[36:68]),
        'timestamp': hex_to_int(s[68:72]),
        'bits': hex_to_int(s[72:76]),
        'nonce': hex_to_int(s[76:80]),
        'BirthdayA': hex_to_int(s[80:84]),
        'BirthdayB': hex_to_int(s[84:88]),
    }


############ functions from pywallet #####################



def hash_160(public_key):
    try:
        md = hashlib.new('ripemd160')
        md.update(hashlib.sha256(public_key).digest())
        return md.digest()
    except:
        import ripemd
        md = ripemd.new(hashlib.sha256(public_key).digest())
        return md.digest()


def public_key_to_pubkey_address(public_key):
    return hash_160_to_pubkey_address(hash_160(public_key))


def public_key_to_bc_address(public_key):
    """ deprecated """
    return public_key_to_pubkey_address(public_key)


def hash_160_to_pubkey_address(h160, addrtype=None):
    """ deprecated """
    if not addrtype:
        addrtype = PUBKEY_ADDRESS
    return hash_160_to_address(h160, addrtype)


def hash_160_to_pubkey_address(h160):
    return hash_160_to_address(h160, PUBKEY_ADDRESS)


def hash_160_to_script_address(h160):
    return hash_160_to_address(h160, SCRIPT_ADDRESS)


def hash_160_to_address(h160, addrtype = 12):
    """ Checks if the provided hash is actually 160bits or 20 bytes long and returns the address, else None
    """
    if h160 is None or len(h160) is not 20:
        return None
    vh160 = chr(addrtype) + h160
    h = Hash(vh160)
    addr = vh160 + h[0:4]
    return b58encode(addr)

def bc_address_to_hash_160(addr):
    if addr is None or len(addr) is 0:
        return None
    bytes = b58decode(addr, 25)
    return bytes[1:21] if bytes is not None else None


def b58encode(v):
    """encode v, which is a string of bytes, to base58."""

    long_value = 0L
    for (i, c) in enumerate(v[::-1]):
        long_value += (256**i) * ord(c)

    result = ''
    while long_value >= __b58base:
        div, mod = divmod(long_value, __b58base)
        result = __b58chars[mod] + result
        long_value = div
    result = __b58chars[long_value] + result

    # Bitcoin does a little leading-zero-compression:
    # leading 0-bytes in the input become leading-1s
    nPad = 0
    for c in v:
        if c == '\0':
            nPad += 1
        else:
            break

    return (__b58chars[0]*nPad) + result


def b58decode(v, length):
    """ decode v into a string of len bytes."""
    long_value = 0L
    for (i, c) in enumerate(v[::-1]):
        long_value += __b58chars.find(c) * (__b58base**i)

    result = ''
    while long_value >= 256:
        div, mod = divmod(long_value, 256)
        result = chr(mod) + result
        long_value = div
    result = chr(long_value) + result

    nPad = 0
    for c in v:
        if c == __b58chars[0]:
            nPad += 1
        else:
            break

    result = chr(0)*nPad + result
    if length is not None and len(result) != length:
        return None

    return result


def EncodeBase58Check(vchIn):
    hash = Hash(vchIn)
    return b58encode(vchIn + hash[0:4])


def DecodeBase58Check(psz):
    vchRet = b58decode(psz, None)
    key = vchRet[0:-4]
    csum = vchRet[-4:]
    hash = Hash(key)
    cs32 = hash[0:4]
    if cs32 != csum:
        return None
    else:
        return key




########### end pywallet functions #######################
import os

def random_string(length):
    return b58encode(os.urandom(length))

def timestr():
    return time.strftime("[%d/%m/%Y-%H:%M:%S]")



### logger
import logging
import logging.handlers

logger = logging.getLogger('electrum')

def init_logger(logfile):
    hdlr = logging.handlers.WatchedFileHandler(logfile)
    formatter = logging.Formatter('%(asctime)s %(message)s', "[%d/%m/%Y-%H:%M:%S]")
    hdlr.setFormatter(formatter)
    logger.addHandler(hdlr)
    logger.setLevel(logging.INFO)


def print_log(*args):
    logger.info(" ".join(imap(str, args)))

def print_warning(message):
    logger.warning(message)

我已经尝试了所有方法，从使用不同的编辑器到重写台词......没有运气

Traceback (most recent call last):
  File "/usr/local/bin/run_electrum_server", line 5, in <module>
    pkg_resources.run_script('electrum-server==0.9', 'run_electrum_server')
  File "/usr/lib/python2.7/dist-packages/pkg_resources.py", line 528, in run_script
    self.require(requires)[0].run_script(script_name, ns)
  File "/usr/lib/python2.7/dist-packages/pkg_resources.py", line 1401, in run_script
    exec(script_code, namespace, namespace)
  File "/usr/local/lib/python2.7/dist-packages/electrum_server-0.9-py2.7.egg/EGG-INFO/scripts/run_electrum_server", line 34, in <module>

  File "build/bdist.linux-x86_64/egg/electrumserver/__init__.py", line 1, in <module>
  File "/usr/local/lib/python2.7/dist-packages/electrum_server-0.9-py2.7.egg/electrumserver/utils.py", line 74
    + int_to_hex(int(res.get('BirthdayA')), 4) \
    ^
IndentationError: unexpected indent
Starting server as daemon
nohup: redirecting stderr to stdout

Answer 1

您的代码在这里没有产生错误。

可能只是制表符/空格缩进的一致性问题:如果你使用4个空格进行缩进，请保持一致，不要使用制表符，否则不同缩进级别的东西可能会排成一行，导致这样的错误。