我在 python 中使用 Selenium。我有超链接列表,我从那里迭代每个超链接并在新选项卡中打开该特定链接,然后使用 Keys.CONTROL + Keys.SHIFT + Keys.RETURN 将焦点放在新选项卡上。
不幸的是,在新选项卡上使用 xpath 选择时,在新选项卡中打开链接失败:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from time import sleep
list_links = self.driver(By.XPATH, "//a/" )
for link in list_links:
link.send_keys(Keys.CONTROL + Keys.SHIFT + Keys.RETURN) #Open new Tab
#get text from new tab webpage.
sleep(50)
data = self.driver.find_element(By.XPATH, "//span/" ).text #ERROR
print data
我能够打开新标签并将焦点设置到新标签(这似乎有效)。但是当我尝试在新选项卡上使用 XPath 时,它会抛出:
NoSuchElementException: Message: no such element.
即使该元素在那里可用。我不知道我在这里做错了什么。任何帮助都将不胜感激。
最佳答案
复制以下代码from this link并显示了如何将焦点切换到另一个选项卡的一些额外步骤。试一试:
browser = webdriver.Firefox()
browser.get('https://www.google.com?q=python#q=python')
first_result = ui.WebDriverWait(browser, 15).until(lambda browser: browser.find_element_by_class_name('rc'))
first_link = first_result.find_element_by_tag_name('a')
# Save the window opener (current window, do not mistaken with tab... not the same)
main_window = browser.current_window_handle
# Open the link in a new tab by sending key strokes on the element
# Use: Keys.CONTROL + Keys.SHIFT + Keys.RETURN to open tab on top of the stack
first_link.send_keys(Keys.CONTROL + Keys.RETURN)
# Switch tab to the new tab, which we will assume is the next one on the right
browser.find_element_by_tag_name('body').send_keys(Keys.CONTROL + Keys.TAB)
# Put focus on current window which will, in fact, put focus on the current visible tab
browser.switch_to_window(main_window)
# do whatever you have to do on this page, we will just got to sleep for now
sleep(2)
# Close current tab
browser.find_element_by_tag_name('body').send_keys(Keys.CONTROL + 'w')
# alternatively, use this, but it was reported that it doesn't always work
# driver.close()
# Put focus on current window which will be the window opener
browser.switch_to_window(main_window)
如果您使用的是 Mac,这可能行不通,但在评论中也给出了解决方法。
或者,this SO answer通过使用选项卡的窗口名称还有另一种解决方法。
更新:如评论中所述,用户使用 Linux(不在 OP 中)。使用以下组合键代替上面代码中提到的默认组合:Keys.CONTROL + Keys.SHIFT + Keys.RETURN
。
关于python - 使用带有 Selenium 的 XPath 打开新选项卡并从该选项卡中获取内容时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32460818/