是否可以在 matplotlib 的图形窗口内选择一个区域并为其分配值(例如 0)?例如,假设我想编写一个脚本,在某个时刻显示图形窗口 (pyplot.imshow) 内的图像,并要求用户选择一个为其分配值 0 的区域? 希望这已经足够清楚了。
最佳答案
这个效果很好。这里有一个 pcolormesh,您可以在其中单击,捕获单击事件的 onclick 函数将处理该事件并将所选方 block 设置为零。 mpl_connect
函数将 onclick
函数连接到 button_press_event
事件。点击后可以直接看到更新。
import numpy as np
import pylab as pl
pl.ioff()
rand_field = np.random.rand(10,10)
fig = pl.figure()
cm = pl.pcolormesh(rand_field, vmin=0, vmax=1)
pl.colorbar()
def onclick(event):
indexx = int(event.xdata)
indexy = int(event.ydata)
print("Index ({0},{1}) will be set to zero".format(indexx, indexy))
rand_field[indexy, indexx] = 0.
cm.set_array(rand_field.ravel())
event.canvas.draw()
cid = fig.canvas.mpl_connect('button_press_event', onclick)
pl.show()
在这里您可以找到一个更高级的版本,可以拖动区域并处理错误,以防有人在图形之外单击。我将矩形的绘制留给您:
import numpy as np
import pylab as pl
pl.ioff()
rand_field = np.random.rand(10,10)
fig = pl.figure()
cm = pl.pcolormesh(rand_field, vmin=0, vmax=1)
pl.colorbar()
x_press = None
y_press = None
def onpress(event):
global x_press, y_press
x_press = int(event.xdata) if (event.xdata != None) else None
y_press = int(event.ydata) if (event.ydata != None) else None
def onrelease(event):
global x_press, y_press
x_release = int(event.xdata) if (event.xdata != None) else None
y_release = int(event.ydata) if (event.ydata != None) else None
if (x_press != None and y_press != None and x_release != None and y_release != None):
(xs, xe) = (x_press, x_release+1) if (x_press <= x_release) else (x_release, x_press+1)
(ys, ye) = (y_press, y_release+1) if (y_press <= y_release) else (y_release, y_press+1)
print("Slice [{0}:{1},{2}:{3}] will be set to zero".format(xs, xe, ys, ye))
rand_field[ys:ye, xs:xe] = 0.
cm.set_array(rand_field.ravel())
event.canvas.draw()
x_press = None
y_press = None
cid_press = fig.canvas.mpl_connect('button_press_event' , onpress )
cid_release = fig.canvas.mpl_connect('button_release_event', onrelease)
pl.show()
关于python - 与python的matplotlib图交互: assign value to selected features,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33231120/